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alex41 [277]
3 years ago
12

How did we transform from f(x) =x2 to g(x) = -3x2

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

Answer:

  f(x) is reflected over the x-axis and vertically scaled by a factor of 3

Step-by-step explanation:

If you compare the two functions, you see that ...

  g(x) = -3f(x)

Multiplication by -1 effects a reflection over the x-axis. (All y-values are transformed to their opposite.)

Multiplication by 3 is a vertical scaling by a factor of 3.

Taken together, f(x) is reflected over the x-axis and vertically scaled by a factor of 3.

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Which expression shows the result of applying the distributive property to 3 (1/5x - 1/7)
Ivan

Hi,

3(1/5x - 1/7)

= 3/5x - 3/7

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2 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
The value of varies directly with . If = 4, then = 12. What is the value of when = 6?
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Find the value of x
Paladinen [302]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 12°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:2x + 6 + 5x + 90 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:7x + 6 = 180 - 90

\qquad❖ \:  \sf \:7x + 6 = 90

\qquad❖ \:  \sf \:7x = 90 - 6

\qquad❖ \:  \sf \:7x = 84

\qquad❖ \:  \sf \:x = 84 \div 7

\qquad❖ \:  \sf \:x = 12

\qquad \large \sf {Conclusion}  :

\qquad❖ \:  \sf \:x = 12 \degree

7 0
2 years ago
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