Answer: It is because tyrosine kinases and BTK have similar solubilities
Explanation:
In column chromatography, components of a mixture are seperated based on their relative solubilities in two non-mixing phases.
In essence, tyrosine kinases and BTK are present in the eluate due to their similar solubility rates that arise from the similar chemical structure both possess (otherwise it would be impossible for the inhibitor meant for Tyrosine kinase to bind and also inhibits BTK)
Thus, the similar solubilities of both groups is the reason they could elute out of the column without being adsorped.
Answer is: the ratio of amount NaOH reacting per unit amount FeCl₃ is 3 mol NaOH /1 mol FeCl₃.
Balanced chemical reaction:
3NaOH(aq) + FeCl₃(aq) → 3NaCl(aq) + Fe(OH)₃(s).
NaOH is sodium hydroxide.
FeCl₃ is iron(III) chloride.
Coefficient for sodium hydroxide is three and for iron(III hydroxide is one.
The factors that affect the rate of solution formation are capable of either increasing the rate of solution formation or decreasing it.
<h3>Factors that affect the rate of solution formation</h3>
The rate of solution formation from a chemical reaction depends on the following factors:
- Quantity of solute and solvent: The solute should be in less quantity and solvent should be more in quantity to dissolve the solute. This will enhance the formation of solution
- The size of the solute particles: When the solute particles are in smaller sizes, they react faster with the solvent to form solutions.
- The temperature of solvent: In increased temperature, the solute reacts faster with the solvent.
Therefore, the factors that affect the rate of solution formation are capable of either increasing the rate of solution formation or decreasing it.
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Answer:
endoplasmic reticulum (ER)
Answer:
25.157 cm³
Explanation:
Data Given:
Mass of Sugar (m) = 40g
Density of sugar given in literature = 1.59 g/cm³
Volume of Sugar = ?
The formula will be used is
d = m/v ........................................... (1)
where
D is density
m is the mass
v is the volume
So
Rearrange the Equation (1)
d x v = m
v = m/ d ................................................ (2)
put the given values in Equation (2)
v = 40g / 1.59 g/cm³
v = 25.157 cm³
volume of 40 g of sugar = 25.157 cm³
