The chemical symbol for a calcium ion is ca2 . what does the 2 symbolize

Which is a compound that contains carbon?

Anastaziya [24]

carbon dioxide, that is what I found

7 0

3 years ago

Which of the following represents the correct ranking in terms of increasing boiling point? A. n-butane < 1-butanol < diet

bonufazy [111]

Answer:

The answer to your question is: letter E

Explanation:

Normally, the correct order of boiling points is:

Alcohols > Ketones > Ether > Alkane

Then

A. n-butane < 1-butanol < diethyl ether < 2-butanone

B. n-butane < 2-butanone < diethyl ether < 1-butanol

C. 2-butanone < n-butane < diethyl ether < 1-butanol

D. n-butane < diethyl ether < 1-butanol < 2-butanone

E. n-butane < diethyl ether < 2-butanone < 1-butanol

(- 1°C) < 34.6°C < 79.64°C < 117.7°C

6 0

3 years ago

The equilibrium constant Kc for the decomposition of phosgene, COCl2, is 4.63x10^-3 at 527 C. Calculate the equilibrium partial

Studentka2010 [4]

Answer: The partial pressure of the $CO,Cl_2\text{ and }COCl_2$ are 0.352 atm, 0.352 atm and 0.408 atm respectively.

Explanation:

We are given:

$K_c=4.63\times 10^{-3}$

$p_{COCl_2}=0.760atm$

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

Where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $4.63\times 10^{-3}$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $527^oC=527+273=800K$

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-1=1$

Putting values in above equation, we get:

$K_p=4.63\times 10^{-3}\times (0.0821\times 800)^{1}\\\\K_p=0.304$

The chemical reaction for the decomposition of phosgene follows the equation:

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

At t = 0 0.760 0 0

At $t=t_{eq}$ 0.760-x x x

The expression for $K_p$ for the given reaction follows:

$K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}$

We are given:

$K_p=0.304\\p_{COCl_2}=0.760-x\\p_{CO}=x\\p_{Cl_2}=x$

Putting values in above equation, we get:

$0.304=\frac{x\times x}{0.760-x}\\\\x=0.352,-0.656$

Negative value of 'x' is neglected because partial pressure cannot be negative.

So, the partial pressure for the components at equilibrium are:

$p_{COCl_2}=0.760-0.352=0.408atm\\\\p_{CO}=0.352atm\\\\p_{Cl_2}=0.352atm$

Hence, the partial pressure of the $CO,Cl_2\text{ and }COCl_2$ are 0.352 atm, 0.352 atm and 0.408 atm respectively.

6 0

3 years ago

What is the answer ?

Blizzard [7]

Answer: 4. A solution in which methyl orange is red

Explanation:

The others solutions are in their basic form while methyl orange is in it’s acidic form when red.

7 0

3 years ago

Read 2 more answers

Freezing point and boiling point of a substance P is -220 0 c and – 185 0c. A t which of the following range of the temperatures

Firlakuza [10]

Answer:

Between -195°C to -215°C

Explanation:

We begin from this data:

P under -220°C will be solid, because -220°C is the freezing point.

Above -220°C, P will be at liquid state.

Then -185°C is the boling point, so above that temperature we have P as a gas.

Between -175°C to -210°C

Above -185°C we said that P is gas, so at -175°C P is not liquid. This state is F.

Between – 190°C to -225°C

At -190°C, we can have P as liquid, but -225°C is under -220°C, where P changes from liquid to solid. Then, this state is also F.

Between -200°C to -160°C

Above -185°C we said that P is gas, so at -160°C P is not liquid. This state is also F. The same, as the first situation.

Between -195°C to -215°C

-195°C is a lower temperature than -185°C. P is still liquid, we did not get the boiling point yet. -215°C is higher than -220°C, P is also liquid. There are still 5°C until P completely freezes. This is the correct choice.

7 0

3 years ago