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Neko [114]
3 years ago
13

What is the volume of a cube with a side length of of a unit?

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0
It’s d times it three times length width height
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? x 10 = 6,026.1 what would be the first number
Nadusha1986 [10]

Answer:

602.61

Step-by-step explanation:

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3 years ago
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Suppose that x has a binomial distribution with n = 201 and p = 0.45. (Round np and n(1-p) answers to 2 decimal places. Round yo
ycow [4]

Answer:

a) It can be used because np and n(1-p) are both greater than 5.

Step-by-step explanation:

Binomial distribution and approximation to the normal:

The binomial distribution has two parameters:

n, which is the number of trials.

p, which is the probability of a success on a single trial.

If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.

In this question:

n = 201, p = 0.45

So, lets verify the conditions:

np = 201*0.45 = 90.45 > 5

n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5

Since both np and n(1-p) are greater than 5, the approximation can be used.

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~PLEASE HELP ASAP OFFERING 12 POINTS~
Anna35 [415]

The answer is definitely 60%

7 0
3 years ago
A garden has 8 white roses and 11 yellow roses
Kisachek [45]
8+11=19. So there’s 19 roses in total
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3 years ago
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Help me out please and thank you
faust18 [17]
<h3>Answer: 1</h3>

========================================================

Explanation:

We're given the height in relation to base BC, so we need to find the length of this base. This is the same as finding the distance from B to C.

Turn to the distance formula

d = \text{Distance from B to C}\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y^2)^2}\\\\d = \sqrt{(-2-(-3))^2+(-1-(-2))^2}\\\\d = \sqrt{(-2+3)^2+(-1+2)^2}\\\\d = \sqrt{(1)^2+(1)^2}\\\\d = \sqrt{1+1}\\\\d = \sqrt{2}\\\\

Coincidentally, the base and height are the same. This won't always be the case.

Now we can find the area of the triangle

A = \text{Area of triangle}\\\\A = \frac{1}{2}*\text{Base}*\text{Height}\\\\A = \frac{1}{2}*\sqrt{2}*\sqrt{2}\\\\A = \frac{1}{2}*\sqrt{2*2}\\\\A = \frac{1}{2}*\sqrt{4}\\\\A = \frac{1}{2}*2\\\\A = 1\\\\

The area of the triangle is 1 square unit.

See diagram below.

5 0
3 years ago
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