Ask question

Ask question

All categories

4 years ago

10

Linear models functions

1 answer:

Roman55 [17]4 years ago

3 0

6/2 + 2 is the correct answer

You might be interested in

What is the value of three in 34,525

LUCKY_DIMON [66]

5=ones
2=tens
5=hundreds
4=thousands
3=ten thousands

7 0

4 years ago

I need help fast will give brainliest!!!

givi [52]

Answer:

C and D

Step-by-step explanation:

the answers are C and D.

6 0

3 years ago

What numbers are multiples of 7 and factors of 28

bija089 [108]

7 and 14 are both multiplies

4 0

4 years ago

Read 2 more answers

Five times the sum of a number and 4 is 9

Mazyrski [523]

Answer:

5x+4=9

Step-by-step explanation:

6 0

3 years ago

F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist

tester [92]

Answer:

$(f - g)(x) = x^2 + x-21$

$(f - g)(10) = 89$

$(f/g)(x) = \frac{x^2 - 10}{11 - x}$

Step-by-step explanation:

Given

$f(x) = x^2 - 10$

$g(x) = 11 - x$

Solving (1): (f-g)(x)

$(f - g)(x) = f(x) - g(x)$

Substitute values for f(x) and g(x)

$(f - g)(x) = x^2 - 10 - (11 - x)$

Open Bracket

$(f - g)(x) = x^2 - 10 - 11 + x$

$(f - g)(x) = x^2 -21 + x$

Reorder

$(f - g)(x) = x^2 + x-21$

Solving (2): (f-g)(10)

In (1)

$(f - g)(x) = x^2 + x-21$

So:

$(f - g)(10) = 10^2 + 10-21$

$(f - g)(10) = 100 + 10-21$

$(f - g)(10) = 89$

Solving (3): (f/g)(x)

$(f/g)(x) = \frac{f(x)}{g(x)}$

Substitute values for f(x) and g(x)

$(f/g)(x) = \frac{x^2 - 10}{11 - x}$

6 0

3 years ago