Answer:
44
Step-by-step explanation:
9514 1404 393
Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
Answer:
5x+4y = 52
Step-by-step explanation:
We can first write the equation in point slope form
y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point
y - 8 = -5/4 ( x-4)
Multiply each side by 4 to get rid of the fraction
4(y - 8) = 4*(-5/4) ( x-4)
4(y - 8) = -5 ( x-4)
Distribute
4y - 32 = -5x+20
We want the equation in the form
Ax + By = C
Add 5x to each side
5x+4y -32 = -5x+5x+20
Add 32 to each side
5x+4y -32+32 =32+20
5x+4y = 52
The first answer
f(x)= (x-3)^2 + 4