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Artist 52 [7]
3 years ago
6

Please answer the following question what is 1+1

Mathematics
2 answers:
horsena [70]3 years ago
6 0

Answer:2

Step-by-step explanation :put both of your finger up

grin007 [14]3 years ago
4 0

The answer to this question is not that hard you just gotta go school

2

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PLEASE HELP ASAP!!!
Mila [183]

Answer:

4. x=0 x=5

5. x=-4 x=8

6 0
3 years ago
the specification for a plastic handle calls for a length of 6.0 inches +- .2 inches. The standard deviation of the process is e
erastova [34]

Answer:

a)

USL = 6.2 inches

LSL = 5.8 inches

b) Cp = 1.33

Cpk = 0.67

c)

Yes it meets all specifications

Step-by-step explanation:

The specification for a plastic handle calls for a length of 6.0 inches ± .2 inches. The standard deviation of the process is estimated to be 0.05 inches. What are the upper and lower specification limits for this product? The process is known to operate at a mean thickness of 6.1 inches. What is the Cp and Cpk for this process?   Is this process capable of producing the desired part?

Given that:

Mean (μ) = 6.1 inches, Standard deviation (σ) = 0.05 inches and the length of the plastic handle is 6.0 inches ± .2

a) Since the length of the plastic handle is 6.0 inches ± .2  = (6 - 0.2, 6 + 0.2)

The Upper specification limits (USL) = 6 inches + 0.2 inches = 6.2 inches

The lower specification limits (LSL) = 6 inches - 0.2 inches = 5.8 inches

b) The Cp is given by the formula:

Cp=\frac{(USL-LSL)}{6\sigma} =\frac{(6.2-5.8)}{6*0.05} =1.33

The Cpk is given by the formula:

c)

The upper specification limit lies about 3 standard deviations from the centerline, and the lower specification limit is further away, so practically all units will meet specifications

Cpk=min(\frac{USL-\mu}{3\sigma},\frac{\mu -LSL}{3\sigma})=min(\frac{6.2-6.1}{3*0.05},\frac{6.1-5.8}{3*0.05})=min(0.67,2)=0.67

7 0
3 years ago
If they are Similar what’s is the similarity statement ?
Bess [88]

Answer:

Show the whole pic

Step-by-step explanation:

6 0
3 years ago
Willy has compounded monthly to invest his summer earnings of $4259 in the
pogonyaev

We have been given that Willy has compounded monthly to invest his summer earnings of $4259 in the  Rock Solid Bank. The bank is offering 6%. We are asked to find the amount of money will be after 5 years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year.

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded monthly, so n=12 and P=4259.

A=\$4259(1+\frac{0.06}{12})^{12\cdot 5}

A=\$4259(1+0.005)^{60}

A=\$4259(1.005)^{60}

A=\$4259(1.3488501525493161)

A=\$5744.752799707\approx \$5744.75

Therefore, Will will have approximately \$5744.75 in 5 years.

7 0
3 years ago
A way to remember corresponding angles is to remember: *
Montano1993 [528]
Haha ahaha hah ahaha haha
3 0
3 years ago
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