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Artist 52 [7]
3 years ago
6

Please answer the following question what is 1+1

Mathematics
2 answers:
horsena [70]3 years ago
6 0

Answer:2

Step-by-step explanation :put both of your finger up

grin007 [14]3 years ago
4 0

The answer to this question is not that hard you just gotta go school

2

You might be interested in
Help needed please and thank you
Dovator [93]
A OK this was hard very hard
4 0
3 years ago
11) Which of the following is zero of the polynomial x^3+x^2+x+1
Mrac [35]

Answer:

<em>Answer: -1</em>

Step-by-step explanation:

<u>The Polynomial Remainder Theorem</u>

It states that the remainder of the division of a polynomial f(x) by (x-r) is equal to f(r).

We have the polynomial:

f(x)=x^3+x^2+x+1

And we need to determine if x=1 and/or x=-1 are zeros of the polynomial.

Considering the polynomial remainder theorem, if we try any value for x, and the remainder is zero, then that value of x is a root or zero of the polynomial.

Find:

f(1)=1^3+1^2+1+1

f(1)=4

Thus, x=1 is not a zero of f(x)

Now, find:

f(-1)=(-1)^3+(-1)^2+(-1)+1

f(1)=-1+1-1+1=0

Thus, x=-1 is a zero of f(x)

Answer: -1

6 0
3 years ago
Solve this into y=mx+b form. I don’t know how to solve this one. Please help me with the steps.
Airida [17]

Hi there!

Here are all the steps into solving this equation into the y-intercept form:

y <u>- 6</u> = 1/2(x - 2)

Add 6 on each side of the equation

y = <u>1/2(x - 2)</u> + 6

Multiply the whole parentheses by 1/2

<u>1/2 × x</u> = 1/2X

<u>1/2 × -2</u> = -1

y = 1/2x <u>- 1 + 6</u>

Add the similar terms together

y = 1/2x + 5 → ANSWER


There you go! I really hope this helped, if there's anything just let me know! :)

8 0
4 years ago
Read 2 more answers
Simplify 3a^2b^2x2ab+6a^3b^2
ira [324]

3 {a}^{2} \times  {b}^{2} \times 2ab + 6 {a}^{3} \times  {b}^{2} =

6 {a}^{3} {b}^{3} + 6 {a}^{3} {b}^{2} =

Factoring 6a^3 b^2

6 {a}^{3} {b}^{2}(b + 1)

_________________________________

I think this is the correct answer.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
5. Solve the equation. 8/x+3 = 1/x+1
Helga [31]

Answer:

x = -5/7

Step-by-step explanation:

8               1

---------- = ----------

x+3           x+1

Using cross products

8 (x+1) = 1 (x+3)

Distribute

8x+8 = x+3

Subtract x from each side

8x-x +8 = x-x+3

7x+8 =3

Subtract 8 from each side

7x +8-8 =3-8

7x = -5

Divide each side by 7

7x/7 = -5/7

x = -5/7

4 0
4 years ago
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