Select all the correct locations on the graph. At which points are the equations y = x2 + 3x + 2 and y = 2x + 3 approximately equal? 2.
Answer:
Step-by-step explanation:
Problem One (left panel)
<em><u>Question A</u></em>
- The y intercept happens when x = 0
- That being said, the y intercept is 50. It was moving when the timing began.
<em><u>Question B</u></em>
The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.
<em><u>Question C</u></em>
- 60 = a + (n-1)d
- 60 = 50 + (n - 1)*2
- 10/2 = (n - 1)*2/2
- 5 = n - 1
- 6 = n
The way I have done it the domain is n from 1 to 6
Question 2 (Right Panel)
<em><u>Question A</u></em>
The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.
- f(0) = ax + b
- -3 = a*0) + b
- b = - 3
- So far what you have is
- f(x) = ax - 3
- f(-1) = a*(-1) - 3 but we know (f(-1)) = -6
- - 6 = a(-1) - 3 add 3 to both sides
- -6 +3 = a(-1) -3 + 3
- -3 = a*(-1) Divide by - 1
- a = 3
- f(x) = 3x - 3 Answer for f(x)
- The slope of f(x) = the coefficient in front of the x
- f(x) has a slope of 3
- g(x) has a slope of 4
<em><u>Part B</u></em>
- f(x) has a y intercept of - 3
- g(x) has a y intercept of -5
- f(x) has the greater y intercept.
- -3 > - 5
Answer:
Hope this solution helps you
It has an infinite amount of solutions.
Explanation:
d-3 = -3+d which can be arranged as: d-3=d-3
Since they are equal to each other, no matter what number you input, your solution will be the same which means that there are an infinite amount of solutions. Let’s put this to the test and put in 5 for d. 5-3=5-3 is 2=2. They are equal to each other which means: infinite solution.
Answer:
<u><em>Measure of angle A is 27 7/9 degrees.</em></u>
Step-by-step explanation:
Lets call measure of angle A is <em><u>X-10</u></em>
Lets call measure of angle B is X
Lets call measure of angle D is 2.5X+20
We know that the sum of triangles add up to 180 degrees
X+X-10+2.5X+20=180
X=37 7/9
So measure of angle A is 27 7/9 degrees.
I hope this is right. :)
