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Readme [11.4K]
4 years ago
5

In the inequality

Mathematics
1 answer:
DanielleElmas [232]4 years ago
4 0
You would add six to both sides then divide by twelve. So Todds age is 16/12 or 1.3333....
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DUE IN 30 MINUTES PLEASE SHOW FULL WORK :[
Dmitry_Shevchenko [17]

Answer:

-3x^2√21x * 5x^2√3x

Step-by-step explanation:

-3x√21x^3 * 5x√3x^3

-3x^2√21x * 5x^2√3x

7 0
3 years ago
Simplify the following expression to an answer with only positive exponents.
yulyashka [42]

Answer:

The correct answer is (edit: b).

Step-by-step explanation:

\frac{(2x^5y^7)(-5x^4z^{-5})}{y^{12}z^6}\\\\\frac{-10x^9y^7z^{-5}}{y^{12}z^6}\\\\\frac{-10x^9}{y^5z^{11}}

3 0
3 years ago
The segments shown below could form a triangle.<br><br> A. True<br> B. False
oksano4ka [1.4K]

Hello There!

False.

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AnimeVines

7 0
3 years ago
Read 2 more answers
find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next
zalisa [80]

Answer:

The number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

Step-by-step explanation:

We need to find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​.

There are 9 letters in the word WONDERFUL

There is a condition that letter R is always next to E.

So, We have two letters fixed WONDFUL (ER)

We will apply Permutations to find ways of arrangements.

The 7 letters (WONDFUL) can be arranged in ways : ⁷P₇ = 7! = 5040 ways

The 2 letters (ER) can be arranged in ways: ²P₂ =2! = 2 ways

The number of ways 'WONDERFUL' can be arranged is: (5040*2) = 10,080 ways

So, the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E​ is 10,080 ways

8 0
3 years ago
What is the value of x?<br>a)×=32<br>b)x=36<br>c)x=37<br>d)x=40​
cestrela7 [59]
? Is there an equation that comes with this problem?
6 0
3 years ago
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