So when a problem asks for distance per meter you know there has to be a fraction involved. So you would put 6 over the fraction 3/8. So simplest form would be to just simplify the fraction. To simplify, you would multiply 8 by the top and bottom which gives you 48/3 minutes per meter. Dividing this gives you the answer 16 minutes per meter. Hope that helps.
When it says how many more that means to subtract and that will be 20
Answer:
P_1st year = P0 x (1 + r/n) = P0 x (1 + r/n)^1
P_2nd year = P0 x (1 + r/n) (1 + r/n) = P0 x (1 + r/n)^2
...
P_n year = P0 x (1 + r/n)^n
Hope this helps!
:)
Answer:
C
Step-by-step explanation:
Okay, here we have a reduction in the number of students by 20% from 2010 to 2011.
In 2011, we had k students, so we want to calculate the number of students we had in 2010.
Let the number of students present in 2010 be x
So mathematically;
x - 20% of x = k
x - 0.2(x) = k
0.8x = k
x = k/0.8
x = k * 1/0.8
x = k * 1.25
x = 1.25k