Answer: 1440
Step-by-step explanation:
To arrange 3 boys and 4 girls such that no two boys are together.
Since boys should be arranged between the girls.
So first arrange the girls.
Assume that the girls are placed, then there will be 5 spaces left for 3 boys.
The number of combinations to fill these places = 
Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways
4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways
Then, the total number of arrangements = 10 x 6 x 24 = 1440
Hence, the required number of arrangements = 1440
Answer:
(−2)×5<(−20)
Step-by-step explanation:
Evaluating the options given :
(−2)×5<(−20)
Open the bracket
- 10 < - 20 (false) ` This expression isn't true
(−2)×(−5)>(−25)
Open the bracket
10 > - 25 (true)
2×5>(−25)
Open the bracket
10 > - 25 (true)
2×(−5)<20
Open the bracket
- 10 < 20
The estimate would be 1200.
We will set up a proportion for this. 10 out of 60 of the sample were tagged, so that is the first ratio. The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top). We do not know the total number so we use a variable:
10/60 = x/200
Cross multiply:
10*x = 60*200
10x = 12000
Divide both sides by 10:
10x/10 = 12000/10
x = 1200
The answer is D) 12
If you need proof, just comment.
