Question

PLEASE HELP FAST!!!!!!!! Which two values of x are roots of the polynomial below?

Answer 1

Given a quadratic equation

$ax^2+bx+c=0$

you can find its solutions with the following formula:

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

You equation is identified by the coefficients

$x^2 - 3x + 5 \iff a = 1,\ b = -3,\ c = 5$

Which means the solutions are

$\dfrac{3 \pm \sqrt{9-4\cdot 5}}{2} = \dfrac{3 \pm \sqrt{-11}}{2}$

So, the answers are B and D