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3 years ago

How much water should we add to 5 gallons of 18% acid solution to dilute it to a concentration of 10%?

Mathematics

1 answer:

KIM [24]3 years ago

5 0

4 gallons of water is needed to dilute to a concentration of 10%.

Step-by-step explanation:

It is given that,

The 5 gallons of water contains 18% of acid solution.

Now, we are asked to find the gallons of water needed to dilute it to a concentration of 10% acid solution.

We obtain the equation by stating that the amount of acid 10% in the water must dilute up to 18%.

For this, x amount of water should be added.

Therefore, the equation is framed as,

⇒ 0.1 (x+5) = 5 (0.18)

⇒ 0.1x + 0.5 = 0.9

⇒ 0.1x = 0.9 - 0.5

⇒ x = 0.4 / 0.1

⇒ x = 4

∴ 4 gallons of water is needed to dilute to a concentration of 10%.

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Answer:

we get the all equation of given condition $M = 2P+1$ & $P=2M+1$ Step-by-step explanation:

Given that,

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we have to check all the apply.

According to question,

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Hence,

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2 years ago

Evaluate the expression if g+2, r+3, and t=11. g+6t

Ivahew [28]

Answer:

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Step-by-step explanation:

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3 years ago

Simplify 7 1/3t−(10 2/3t−6) pls

Flura [38]

Answer:

$-\frac{10t}{3}+6$

Step-by-step explanation:

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Convert $7\frac{1}{3}$ to a mixed number

$7\frac{1}{3}=\frac{7\cdot 3+1}{3}$

$=\frac{22}{3}$

$\bold{\frac{22}{3}t-\left(10\frac{2}{3}t-6\right)}$

Convert $10\frac{2}{3}$ into a mixed number

$10\frac{2}{3}=\frac{10\cdot 3+2}{3}$

$=\frac{32}{3}$

$\bold{\frac{22}{3}t-\left(\frac{32}{3}t-6\right)}$

$=\frac{22t}{3}-\frac{32t}{3}+6$

$\bold{=\frac{-10t}{3}+6}$

Terms

Follow the PEMDAS order of operation:

P = Parenthesis
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction

You do these steps in the order for which the equation comes. For example, start with the exponents if there are not any parentheses.

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