Ralph is 3 years old
Casey is 18 years old
Step-by-step explanation:
Let the age of Ralph be x
Then Casey is 6 times as old as Ralph will be 6x
In two years
Ralph =x+2
Casey=6x+2 ⇒ 4(x+2)
Equate the two equations for Casey as
6x+2 = 4x+8
6x-4x=8-2
2x=6
x=6/2= 3
Current age;
Ralph= x= 3 years old
Casey=6x = 6*3= 18 years
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Forming expressions and solving equations;brainly.com/question/1280754
Keywords :six, times, years
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Answer:
Hi!
First you would start at -4 on the x-axis, then you would move up 3 spaces and put your point there.
The x-axis is the horizontal line, and the y-axis is the vertical line.
I hope this helps you!
<span>a1= (which is the first term.)
to find the 2nd term you plug in 2 for (an) in the formula given to you. =-4(2-1)^2 *remember an represents the term u are looking for *
now you start to solve it
-4(2-1)^2
-4 (1)^2
.
-4^2
= 16
so your first two terms are 2 and 16 .</span>
4/5 of x -3/4 of x =5
solution by LCM
16x-15x/20 =5
x/20 =5
x=100
<span>answer 100</span>
X=8 I’m not that to sure but hope i helped!
