How to come out as bi at 14 Please help i need to know
2 answers:
You might be interested in
The given function is
f(x) = x - ln(8x), on the interval [1/2, 2].
The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²
A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079
The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.
Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)
f(x) = x - ln(8x), on the interval [1/2, 2].
The derivative of f is
f'(x) = 1 - 1/x
The second derivative is
f''(x) = 1/x²
A local maximum or minimum occurs when f'(x) = 0.
That is,
1 - 1/x = 0 => 1/x = 1 => x =1.
When x = 1, f'' = 1 (positive).
Therefore f(x) is minimum when x=1.
The minimum value is
f(1) = 1 - ln(8) = -1.079
The maximum value of f occurs either at x = 1/2 or at x = 2.
f(1/2) = 1/2 - ln(4) = -0.886
f(2) = 2 - ln(16) = -0.773
The maximum value of f is
f(2) = 2 - ln(16) = -0.773
A graph of f(x) confirms the results.
Answer:
Minimum value = 1 - ln(8)
Maximum value = 2 - ln(16)
Answer:
.
Step-by-step explanation:
Two vectors and
are parallel to one another if and only if the ratio between their corresponding components are equal:
.
Equivalently:
.
For the two vectors in this equation to be parallel to one another:
.
Solve for :
.
would be the only valid value of
; no other value would satisfy the
equation.
Answer:
The correct option is 3.
Step-by-step explanation:
The HL theorem states that 'if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.'
From the given figure it is noticed that triangle ABC and triangle EDC. In triangle ABC and triangle EDC, hypotenuses of triangles are AB and DE respectively.
To use HL hypotenuse and one leg of triangles must be equal.
(hypotenuse)
(leg)
(leg)
Therefore the additional information will allow you to prove the triangles congruent by the HL Theorem. Option 3 is correct.