10*6=60 un the way it is easy
Given:
The expression is:
![6x^2+3x+21](https://tex.z-dn.net/?f=6x%5E2%2B3x%2B21)
To find:
The factor of the given expression by GCF.
Solution:
We have,
![6x^2+3x+21](https://tex.z-dn.net/?f=6x%5E2%2B3x%2B21)
Here, 3 is the greatest common factor (GCF) of
.
Taking out GCF, we get
![6x^2+3x+21=3(2x^2+x+7)](https://tex.z-dn.net/?f=6x%5E2%2B3x%2B21%3D3%282x%5E2%2Bx%2B7%29)
Therefore, the required factor form of the given expression is
.
$6x$5=$30
$50-$30=$20
So 5 books?
Or
50=6x5+x
x=20
Answer: it’s A and D
Step-by-step explanation:
Answer:
3/12: terminating; 2/9: repeating
Step-by-step explanation:
3/12=0.25 terminating as it has a finite number of digits after the decimal point.
2/9=0.222.... repeating decimal as its number is repeated indefinitely.