Answer:
A partir del problemas vamos a crear una ecuación donde X es una docena de huevos y Y una libra de mantequilla
entonces: 4 docenas de huevos y 3 libras de mantequilla es igual a 14.100
en mi primera ecuación seria: 4X + 3Y = 14.100
ahora haremos la segunda ecuacion: tres docenas y 1 libra de mantequilla
en mi segunda ecuación seria: 3X + 1Y = 8.700 el plan es sumar las dos ecuaciones pero yo quiero que al sumarlas la variable "Y" desaparezca así que mi segunda ecuación la voy a multiplicar pór (-3) quedándome todo así:
primera ecuación: 4X + 3Y = 14.100
segunda ecuacion multiplicada por -3: -9X - 3Y = -26.1
al sumarlas obtengo como resultado: -5X = -12
resolviendo esa ecuacion obtengo que X=
X=2.4
luego reemplazas X en la primera ecuación: 4X + 3Y = 14.100
reemplazando seria: 4 x (2.4) + 3Y =14.100
9.6 + 3Y = 14.1000
3Y= 14.100 - 9.6
Y=
Y=1.5
entonces concluimos que la docena de huevos cuesta 2.4 $ y la libra de mantequilla 1.5 $
Step-by-step explanation:
Answer:
Kaitlin's account will have 72% of the money initially invested, that is, about $ 6,192.
Step-by-step explanation:
Given that last year Kaitlin opened an investment account with $ 8,600, and at the end of the year, the amount in the account had decreased by 28%, to determine the year-end amount in terms of the original amount both in whole numbers and in decimals, the following calculation must be performed:
100 - 28 = 72
8,600 x 0.72 = X
6.192 = X
Thus, Kaitlin's account will have 72% of the money initially invested, that is, about $ 6,192.
2(10v - 5) + 5v + 5v =
= 20v - 10 + 5v + 5v =
= 20v + 5v + 5v - 10 = <u>3</u><u>0</u><u>v</u><u> </u><u>-</u><u> </u><u>1</u><u>0</u> ← the end
Answer:
Step-by-step explanation:
What you are doing is removing the brackets. That shows up as multiplying both terms inside the brackets by the factor outside the brackets (2).
This is a classic example of the distributive property.
Answer:
The answer is below
Step-by-step explanation:
Given that:
Mean (μ) = 1.93, standard deviation (σ) = 1.08 pounds, sample (n) = 62.
the mean weight of discarded plastic for all household is given by:
The standard deviation of discarded plastic for all household is given by:
The confidence (c) = 90% = 0.9
α = 1 - c = 1 - 0.9 = 0.1
α/2= 0.1/2 = 0.05
The z score of 0.05 corresponds to the z score of 0.45 (0.5 - 0.05) which is 1.645. i.e.
The margin of error (E) =
The confidence interval =
We are 90% confidence that the value is between 1,7044 and 2.1556