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SashulF [63]
3 years ago
9

The perimeter, P, of a rectangle is found using the formula P = 2l + 2w, where l is the length of the rectangle and w is the wid

th of the rectangle.
Solve the formula for w.
Mathematics
2 answers:
pogonyaev3 years ago
4 0

Answer:

(P - 2l)/2

Step-by-step explanation:

alexgriva [62]3 years ago
3 0

Answer:The formula to find the perimeter of a rectangle is: P = 2W + 2L. To solve for " W " in this formula, which steps should be followed?

Step-by-step explanation:

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A survey of 120 teachers determined the following:
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Step-by-step explanation:

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Help me please if you can
zheka24 [161]

Answer:

perimeter = 1 3/4

Step-by-step explanation:

1. 3/4 x 2 because there are two sides with the fraction 3/4. 3/4 x 2 is 1 1/2

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8 0
2 years ago
Suppose that the mean time that visitors stay at a museum is 94.2 minutes with a standard deviation of 15.5 minutes. The standar
Maurinko [17]

Answer:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

Step-by-step explanation:

For this case we know that mean time that visitors stay at a museum is given by:

\bar X = 94.2

The standard deviation is given by:

s= 15.5

And the standard error is given by:

SE = \frac{s}{\sqrt{n}} =3.1

And we want to interval captures 68% of the means for random samples of 25 scores and for this case the critical value can be founded like this using the normal standard distribution or excel:

z_{\alpha/2}= \pm 0.994

We can find the interval like this:

\bar X \pm ME

And replacing we got:

94.2 -0.994*3.1 = 91.1186

94.2 +0.994*3.1 = 97.2814

And the 68% confidence interval is given by (91.1186, 97.2814)

7 0
3 years ago
2. If you used the 23 cm basketball as your Moon sphere, how big
castortr0y [4]

Ok so I heard this question a few times already and couldn't remember how it went so I decided to put my brain to the test, I used my algebra to use and complete it.

If the Earth were shrunk down to the size of a basketball (radius:4.69 inches) the Moon would be a tennis ball (radius: 1.2768 inches, to be exact) 23.5 feet away.

The Sun would be a 42.6-foot sphere (source) located 1.7 miles away.

The closest star, Proxima Centauri, would still be 463,151 miles away – almost twice the distance of the actual moon."

6 0
3 years ago
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