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Rashid [163]
2 years ago
11

Been trying to solve this, need help

Mathematics
1 answer:
Alenkasestr [34]2 years ago
7 0

<u>Given</u><u> </u><u>:</u><u>-</u>

  • The given triangle is isosceles triangle.
  • Length of one side is 4 .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of x in simplest radical form.

<u>Solution</u><u> </u><u>:</u><u>-</u>

The given triangle is a right isosceles triangle . So here we can use the Pythagoras theorem as ,

\longrightarrow hypotenuse² = perpendicular ² + base²

\longrightarrow x² = 4² + 4²

\longrightarrow x² = 16 + 16

\longrightarrow x² = 32

\longrightarrow x = √32

\longrightarrow x = √2⁵

\longrightarrow x = 4 × 1.732

\longrightarrow x = 6.928 ≈ 7

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Now, since we know that 5.9 is the amount of miles per day, we need to determine how many miles per month.

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5.9 * 20 = 118

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3 years ago
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Dmitry [639]

Answer:

Rounding to nearest hundredths gives us r=0.06.

So r is about 6%.

Step-by-step explanation:

So we are given:

A=P(1+r)^t

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A=P(1+r)^t

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Take the 6th root of both sides:

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Most likely we are asked to round to a certain place value.

I'm going to put my value for r into my calculator.

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jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

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nata0808 [166]

Answer:

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Step-by-step explanation:

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