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steposvetlana [31]

3 years ago

15

Find 5x-3y-z if x=-2 y=2 and z=-3

1 answer:

kakasveta [241]3 years ago

8 0

Answer:

z=23

Step-by-step explanation:

z=2

You might be interested in

If two events a and b are independent and you know that p(a) = 0.65, what is the value of p(a | b)?

Ksivusya [100]

Let's think of an example which would better help visualize this situation.

1) Someone exercises a lot so they can concentrate more on their homework (here running and concentration on homework are dependent events)

2) Someone exercises a lot because they wear a blue t-shirt (here, you can clearly see that wearing a blue shirt and exercising are not related. These events are independent).

Now concentrating on P(a | b) = Probability a occurred if b occurred.

It does not matter if b occurred (just like it didn't matter that the person wore a blue shirt which meant that they exercised) for the outcome a to occur.

Therefore, probability of P(a | b) = P(a)

P(a | b) = 0.65

Hope I helped :)

5 0

3 years ago

Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ

Georgia [21]

The y-intercept of a function is the point where the graph crosses the $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
The y-intercept is -13.5
The standard equation of the function is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

$\mathbf{x = 10}$

$\mathbf{x = -3}$

$\mathbf{x = -9}$

Equate the above points to 0

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Multiply the above equations

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}$

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }$

Expand

$\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }$

$\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }$

Expand

$\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }$

Collect like terms

$\mathbf{x^3 + 12x^2 - 10x^2+ 27x - 220x - 270 = 0 }$

$\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }$

Replace 0 with y

$\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Hence, the standard form is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Read more about graphs and functions at:

brainly.com/question/18806107

3 0

3 years ago

Beatrice buys a dishwasher for her new house. The price of the dishwasher is D dollars, and she pays an additional 2% tax.

Lubov Fominskaja [6]

The answers are as follows:
Box 1) D
Box 2) .02D
Box 3) D + .02D

7 0

3 years ago

Read 2 more answers

Add.910+(−45).Write your answer as a fraction in simplest form

gavmur [86]

-44.09 i dont understand why we must have 20 characters but OK

3 0

3 years ago

1) If the perimeter of triangle STU is 125 cm, and segments TW, VW, and VT measure 21 cm, 30 cm, and 24 cm, respectively, what i

liq [111]

GIVEN: The perimeter of triangle STU is 125.

The segments TW=21 cm

VW=30 cm

VT=24 cm

TO FIND: The length of the segment SU.

SOLUTION:

As corresponding sides must be same. so we have,

$\frac{TV}{TS}=\frac{TW}{TU}\\\\ \frac{24}{TS}=\frac{21}{TU}\\\frac{TU}{TS}=\frac{7}{8}=k(say)\\$

Then, TU=7k and TS=8k

$\frac{TV}{TS}=\frac{VW}{SU}\\\\ \frac{24}{TS}=\frac{30}{SU}\\\frac{24}{8k}=\frac{30}{SU}\\SU=10k$

As the perimeter of triangle STU is 125.

so,

8·k+7·k+10·k=125

⇒25.k=125

⇒k=5

Therefore, SU=10×5=50

4 0

3 years ago