Remark
This is quite a nice little problem. It takes a minute or three to figure out the answer, and when you do, you will be certain that you have been tricked. It is a little like the egg of Columbus.
Solution
The Base of Triangle ABN is AB
The Base of Triangle CDM is CD
The height of both given triangles is h. That is the distance between the two parallel lines.
Area ABN = 1/2*AB * h = 23 cm^2
Area CDM = 1/2*CD * h = 18 cm^2
Now the Area of the trapezoid is
Area_Trapezoid = 1/2 * h (AB + CD) Using the distributive property Remove the brackets.
Area_Trapezoid = 1/2*AB*h + 1/2*CD*h Did you notice something? Those terms are just the area of the triangles (written above.)
Area Trapezoid = 23 + 18 = 41 cm^2 <<<< Answer
Answer:
Length = 4 inches
Step-by-step explanation:
Perimeter of a rectangle = 2(length + width)
If x = 2
Perimeter = 8x - 4
= 8(2) - 4
= 16 - 4
= 12 inches
Width = 3x - 4
= 3(2) - 4
= 6 - 4
= 2 inches
Perimeter of a rectangle = 2(length + width)
12 = 2(length + 2)
12 = 2length + 4
12 - 4 = 2 length
8 = 2 length
Length = 8/2
Length = 4 inches
Answer:
a
Step-by-step explanation:
I think so..
My guess is that you're doing the Law of Cosines? You have everything you need for that except the angle theta, which is the thing you need to find. It's set up like this: (8)^2 = (10)^2 + (5)^2 -[2(10)(5)cos A] I used A instead of theta. Doing that math, you have: 64 = 100 + 25 -[ 100 cos A]; 64 = 125 - 100 cos A;
-61 = - 100 cos A; -61 / -100 = cos A; .61 = cos A. Now use your inverse function on your calculator to find cos^-1(.61) and that equals 52.4
Answer:
Step-by-step explanation:
The length is x2 while the width is x1.5
Therefore it cannot be a scaled copy