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Elden [556K]
3 years ago
7

What is the name of the lake located at letter B on the map above? Answer is C :)

Mathematics
1 answer:
astraxan [27]3 years ago
3 0

Answer:

the answer is C. lake Texoma

hope this helps

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Solve -24 + (1-4)^2​
ElenaW [278]

Answer:

-15

Step-by-step explanation:

-24 + (1-4)^2​    (solve parentheses first)

= -24 + (-3)^2 (solve exponent)

= -24 + 9

= -15

6 0
3 years ago
Read 2 more answers
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0
3 years ago
Ming has a standard 52-card deck. A standard 52-card deck has 4 suits (♠, ♣,♦, and ♥) and an equal number of cards of each suit.
soldier1979 [14.2K]

Answer:

Option D.

Step-by-step explanation:

Total number of cards = 52

Total number of cards of each suit (♠, ♣,♦, and ♥) = 13

The probability of getting a card of heart is

\text{Probability of getting a card of heart}=\frac{\text{Number of heart cards}}{\text{Total number of cards}}

\text{Probability of getting a card of heart}=\frac{13}{52}

\text{Probability of getting a card of heart}=\frac{1}{4}

The probability of getting a card other then heart is

1-\frac{1}{4}=\frac{3}{4}

If Ming randomly draw a card from the deck 300 times, putting the card back in the deck after each draw, then the number of cards she will draw something other than a heart is

300\times \frac{3}{4}=225

Close to 225 times but probably not exactly 225 times.

Therefore, the correct option is D.

3 0
3 years ago
HELP FAST!!!!!!!!!!!!!!<br> What is the solution to the image?
STALIN [3.7K]

Answer:

x=8

Step-by-step explanation:

We have been given with the function:  

Here, we have same base of logarithmic function on both sides of the equation.

So, we will equate the values on right hand side and left hand side of the equation we will get  

After simplification we will get  

After further simplification we will get  

Hence,  

Therefore the correct answer is 8.

7 0
3 years ago
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