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Snowcat [4.5K]
3 years ago
8

Is the mass of the reactants always equal to the mass of the products in a chemical reaction?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0

Answer: Yes, the mass of the reactants always equal to the mass of the products in a chemical reaction.

Explanation:

In a balanced chemical reaction, the mass of reactants is always equal to the mass of product that is a chemical reaction follows follows 'Law of Conservation of Mass'.

The law states that ' in a chemical reaction mass can neither be created nor be destroyed.

For example: 2H_2+O_2\rightarrow 2H_2O

Mass of the reactants = Mass of products

2(2\times 1amu)+1(2\times 16amu)=2(2\times 1amu+16amu)

36 amu = 36 amu

Yes, the mass of the reactants always equal to the mass of the products in a chemical reaction.

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A sample of quartz is put into a calorimeter (see sketch at right) that contains of water. The quartz sample starts off at and t
pashok25 [27]

Answer:

0.71 J/g°C

Explanation:

Here is the complete question

thermometer A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample starts off at 97.8 °C and the temperature of the water starts off at 17.0 °C. When the temperature of the water stops changing it's 19.3 °C. The pressure remains constant at 1 atm. insulated container water sample Calculate the specific heat capacity of quartz according to this experiment. Be sure your answer is rounded to 2 significant digits. a calorimeter g °C

Solution

Since the temperature of the water increases from 17.0 °C to 19.3 °C, it means that it loses heat. Also, the final temperature of the quartz equals the final temperature of the water 19.3 °C. Since the quartz temperature decreases from 97.8 °C to 19.3 °C it loses heat.

So, heat lost by quartz, Q = heat gained by water, Q'

-Q = Q'

-mc(θ₂ - θ₁) = m'c'(θ₂ - θ₃) where m = mass of quartz = 51.9 g, c = specific heat capacity of quartz, θ₁ = initial temperature of quartz = 97.8 °C, θ₂ = final temperature of quartz = 19.3 °C, m' = mass of water = 300 g, c = specific heat capacity of water = 4.2 J/g °C , θ₃ = initial temperature of water = 17.0 °C, θ₂ = final temperature of water = 19.3 °C

Making c subject of the formula, we have

c = -m'c'(θ₂ - θ₃)/m(θ₂ - θ₁)

Substituting the values of the variables into the equation, we have

c = -300 g × 4.2 J/g °C(19.3 °C - 17.0 °C)/51.9 g(19.3 °C - 97.8 °C)

c = -1260 J/°C(2.3 °C)/51.9 g(-78.5 °C)

c = -2898 J/-4074.15 g°C

c = 0.711 J/g°C

c ≅ 0.71 J/g°C to 2 significant digits

5 0
3 years ago
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Karo-lina-s [1.5K]
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5 0
3 years ago
Calculate the number of moles of C2H6 in 6.29×1023 molecules of C2H6.
Kipish [7]

1.05moles

Explanation:

Given parameters:

Number of molecules of C₂H₆ = 6.29 x 10²³molecules

Unknown:

Number of moles = ?

Solution:

The mole is the amount of substances that contains Avogadro's number of particles i.e 6.02 x 10²³

 To find the number of moles:

  number of moles = \frac{number of particles}{Avogadro's number}

  number of moles = \frac{6.29 x 10^{23} }{6.02 x 10^{23} }

  number of moles = 1.05moles

Learn more:

moles brainly.com/question/1841136

#learnwithBrainly

7 0
3 years ago
This equation shows a ____ refer to this summary equation of photosynthesis to complete the sentences about chemical bonds and r
coldgirl [10]

The balanced chemical equation representing the process of photosynthesis is:

6 CO_{2} +12H_{2}O-->C_{6}H_{12}O_{6}+6O_{2}

The reactants in the process of photosynthesis are CO_{2}and HH_{2}O and the products of the reaction are glucose C_{6}H_{12}O_{6} and oxygen O_{2}. Oxygen is the nonpolar covalent gas which is released in the process of photosynthesis. The reactant CO_{2} is a nonpolar covalent gas while the other reactant waterH_{2}O has polar covalent O-H bonds.

In the balanced chemical equation, the number of each type of element must be equal on both sides of the reaction.

6 0
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If the atomic number of an element is 16, then it has 16 electrons.<br> True<br> False
Aleks04 [339]
True hope this helped u out cuh
4 0
3 years ago
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