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3 years ago

Is the mass of the reactants always equal to the mass of the products in a chemical reaction?

Chemistry

1 answer:

Sunny_sXe [5.5K]3 years ago

5 0

Answer: Yes, the mass of the reactants always equal to the mass of the products in a chemical reaction.

Explanation:

In a balanced chemical reaction, the mass of reactants is always equal to the mass of product that is a chemical reaction follows follows 'Law of Conservation of Mass'.

The law states that ' in a chemical reaction mass can neither be created nor be destroyed.

For example: $2H_2+O_2\rightarrow 2H_2O$

Mass of the reactants = Mass of products

$2(2\times 1amu)+1(2\times 16amu)=2(2\times 1amu+16amu)$

36 amu = 36 amu

Yes, the mass of the reactants always equal to the mass of the products in a chemical reaction.

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3 years ago

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3 years ago

How much energy is used to melt 44.33 g of solid oxygen?

Nutka1998 [239]

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm = 54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J

b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.

Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J

Q2 = Qm * m = 615 J

Qtotal = 177.442 + 615 = 792.44 J

Explanation:

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3 years ago

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