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faltersainse [42]
4 years ago
7

Rectangle RSTU undergoes a dilation centered at the origin. The result is rectangle R'S'T'U'. Which rule describes the dilation?

Mathematics
2 answers:
Elena L [17]4 years ago
4 0

Answer:

The rule is as follows:

x'=5*x

y'=5*y

Step-by-step explanation:

Each coordinate gets scaled by a factor of 5.

For example:

R(-2,0) --> R'(-10,0)    [-2-->5*(-2), 0-->0]

and similarly with the other points S, T, and U

Paul [167]4 years ago
4 0

Answer:

(x, y) → (5x, 5y)

Step-by-step explanation:

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Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 117 mg/dl and
TiliK225 [7]

Answer:

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 117, \sigma = 10.6, n = 6, s = \frac{10.6}{\sqrt{6}} = 4.33

What is the level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L ?

This is the value of X when Z has a pvalue of 1-0.01 = 0.99. So X when Z = 2.33.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

2.33 = \frac{X - 117}{4.33}

X - 117 = 2.33*4.33

X = 127.1

The level L such that there is probability only 0.01 that the mean glucose level of 6 test results falls above L is L = 127.1 mg/dl.

6 0
4 years ago
Identify the constant of proportionality
MissTica
The answer is #2. 3/2. The dot rises 3 lines and moves to the right 2 lines.
7 0
3 years ago
Please help asap <3333333
SOVA2 [1]

Answer:

1: 75 degrees

2: 112 degrees

3: 125 degrees

4: 67 degrees

Step-by-step explanation:

4 0
3 years ago
I need help in math ;pmdjew2kedfheyuwikejhuwiqo
Licemer1 [7]

Answer:

30/343

Step-by-step explanation:

to find the volume of a rectangle you multiply all three fraction

5/7*3/7*2/7

5/7*3/7=15/49

15/49*2/7=30/343

30/343

5 0
3 years ago
What is 9 is 12% of which number???
ASHA 777 [7]
9 is 12% of 75 check it 9* 100 = 900 / 75 = 12
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