The complete question in the attached figure
we know that
[area of a circle]=pi*r²
for r=1 unit
[area of a circle]=pi*1²---------> pi units²
if the area a full circle of 360°--------------> is pi
the area of sector 88°------------------------> X
X=88*pi/360--------> 0.77 units²
the answer is
<span>
the area of sector AOB is 0.77 units</span>
²
P = (2.5,0)
T=(-1.5,-1)
Point R is located (1.5 -2.5)
Answer:
1.x^2
2.x+8
3.x
4. 8x
Step-by-step explanation:
Length of old is x inches.
Because it is square we have that area of the old canvas : 
When we read : width of new is increased by 8 so : x+8
Length is x.
The difference of areas:
Old canvas : A1=
New canvas : 
Now we can find A2-A1:
