Question

What are the approximate values of the non-integral roots of the polynomial equation?

Answer 1

Answer: D: 1.27    E: 4.73

Step-by-step explanation: D & E are right on edg

Answer 2

Answer:

-4, -2, -3-2i, -3+2i

Step-by-step explanation:

The of the polynomial equation are those values of x, for which f(x)=0.

Consider equation

$f(x)=0\\ \\(x^2+6x+8)(x^2+6x+13)=0$

By zero product property,

$x^2+6x+8=0\ \text{or}\ x^2+6x+13=0$

Solve each equation:

1. $x^2+6x+8=0$

$D=6^2-4\cdot 8=36-32=4\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2$

2. $x^2+6x+13=0$

$D=6^2-4\cdot 13=36-52=-16=16i^2\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{16i^2}}{2}=\dfrac{-6\pm 4i}{2}=-3-2i,\ -3+2i$