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ArbitrLikvidat [17]
3 years ago
11

a square rug has a perimeter of 64 cm. george says the side lenght of the square is 8cm . bob thinks it is 16cm. who is correct

?
Mathematics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

16 cm

Bob is correct

Step-by-step explanation:

Perimeter of a square = 4 × side’s length

Then

the side length = 64/4 = 16

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Question 71
yuradex [85]

Answer:

given

p=q^3

p=40

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q=(p)^1/3

q=(40)^1/3-->q=2(5)^1/3

Now

the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.

finally the value of p gonna be

p=q^3

p=(5^1/3) ^ 3

p=5

3 0
3 years ago
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So every week in my class we do a riddle and if you’re able to solve 3 of these correctly in a row you get a prize (homework pas
BARSIC [14]

Answer:

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Step-by-step explanation:

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2 years ago
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Eight children are divided into two teams each containing 4 children. how many different divisions are possible?
Alekssandra [29.7K]
So this is what's known as a combination. a combination is a group where the order does not matter. to solve a combination, you use this equation:
n! / (r! *(n-r)!) 
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r is the group you need to sort them into (4)
(i know it's 2 groups of 4 but if you solve this for 1 group, the other group is automatically made of the remaining kids)
definition of !:
a number with a ! means 1*2*3...*that number (so that number multiplied by every number smaller than it all the way to one)

so we put 8 and 4 in this equation:
8! / (4! *(8-4)!) 
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8! / *(4! 4!) 
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(8*7*6*5*4*3*2*1) / (4*3*2*1 * 4*3*2*1)
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4 0
3 years ago
The sum of two numbers is 23. Twice one number increased by 6 is the same as 4 times the other number decreased by 2. What is th
Crank

Answer:

One number is 4.2, the other is 18.8

Step-by-step explanation:

1.)  x+y=23

    (x+6y)x2=4

2.) (x+6y)x2=4   =   2x+12y=4

3.)Use elimination/substitution to solve

     2x+12y=4  =   x+6y=2  =  x=2-6y

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4.)Solve for y

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5.)Solve for x

    x+4.2=23

    x=18.8

I may be wrong so let me know if I am

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2 years ago
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All of the positive numbers you can think of without a decimal point is greater than all of those  numbers .
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