Given y = (2x + 3)2, what is the standard form of the given quadratic equation.

Mathematics

1 answer:

alexandr402 [8]3 years ago

8 0

Answer:

$y=4x^2+12x+9$

Step-by-step explanation:

Perform the square of the binomial, combine like terms, and then write the remaining expression in decreasing order of powers of x:

$y=(2x+3)^2\\y=(2x+3)\,(2x+3)\\y=4x^2+6x+6x+9\\y=4x^2+12x+9$

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$y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

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$\frac{3wx}{ \sqrt{2y} } = \frac{5}{2z} \\ \\ \sqrt{2y} \times 5 = 3wx \times 2z \\ \\ \sqrt{2y} \times 5 = 6wxz \\ \\ \sqrt{2y} = \frac{6wxz}{5} \\ \\ {( \sqrt{2y} })^{2} = {( \frac{6wxz}{5} })^{2} \\ \\ 2y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \div 2 \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \times \frac{1}{2} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{50} \\ \\ \\ y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

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