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seropon [69]
2 years ago
12

Sam got 10 cookies and his sister took 3 away from him. How much does sam have left?​

Chemistry
1 answer:
Julli [10]2 years ago
4 0

Answer:

he would have 7 cookies left.

Explanation:

This is because 10 - 3 = 7

If you have any questions feel free to ask in the comments - Mark

ALSO Happy Valentines Day ❤

 

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Calculate the molar concentration of the Br⁻ ions in 0.065 M MgBr2(aq).
steposvetlana [31]
MgBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of MgBr2 that dissolves.
MgBr2(s) --> Mg+(aq) + 2 Br⁻(aq)
            [Br⁻] = 0.065 mol MgBr2/1L × 2 mol Br⁻ / 1 mol MgBr2 = 0.13 M
The answer to this question is [Br⁻] = 0.13 M
4 0
3 years ago
Is it possible for the equivalence point of a titration to not be at pH 7? Explain your answer.
lara31 [8.8K]
<span>The reason it will be 7 for some titrations is that when you  titrates a strong acid with a strong base for example  HCl and NaOH the salt formed is conjugate base of strong acid and will be a very weak base
 That means that it cannot produce any OH^-1 and all the H+ has been converted to water.The only source of H+ or OH is water with a Ka of 10^-14 so the pH = -log [H+]=-log 10^-7 = 7 
second reason is 
When you titrates a weak acid with strong base at equivalence point 
only a water solution of the conjugate base exists 

CH3COOH + NaOH ----- Na+ CH3COO^-1 + H2O 
Since the conjugate base is the conjugate base of a weak acid it will hydrolyze in water like so 
for instance Na+ CH3COO^-1 + HCl---- CH3COOH + NaCl the equivalence point will be way BELOW 7 and in the case of above will be less than 5. So pH of 7 at equivalence point is only reached in strong acid strong base titrations.
hope this helps</span>
5 0
3 years ago
Read 2 more answers
Why is peer review an Important part of the scientific process
guajiro [1.7K]
Peer review involves subjecting the author's scholarly work and research to the scrutiny of other experts in the same field to check its validity and evaluate its suitability for publication. A peer review helps the publisher decide whether a work should be accepted.
7 0
3 years ago
Twenty five grams of Iron 3 oxide react with an excess of carbon monoxide to form 15 g of Fe. Carbon dioxide is the other produc
densk [106]
<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

Step 1: Moles of iron (iii) oxide

Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

                                     = 0.156 moles

Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

                              = 0.156 moles × 2

                              = 0.312 moles

Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

                    = 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

            = (15 g ÷ 17.42 g) × 100 %

            = 86.11%

7 0
2 years ago
A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul
yulyashka [42]

Answer:

Atomic mass of E is 128.24

Explanation:

  • The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
  • In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

         E₃ = 384.729

Therefore; E = 384.729 ÷ 3

                     = 128.24  

The atomic mass of E is 128.24

6 0
2 years ago
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