The correct word to fill the blank in the sentence is "capillaries". The thinnest blood vessels in your body are the capillaries. These are the blood vessels that blood is able to transfer sugars and oxygen into the tissues.
Answer:
V = 1.2 × 10⁻⁶ m³
Explanation:
Volume is equal to length × width × height, since we are given these measurements in the question we can simply plug our numbers into the formula.
V = l × w × h
V = 1.64 x 10⁻² × 1.5 x 10⁻² × 4.8 x 10⁻³
V = 1.2 × 10⁻⁶ m³
Answer:
[N2] = 0.3633M
[H2] = 1.090M
[NH3] = 0.2734M
Explanation:
Based on the reaction of the problem, Kc is defined as:
Kc = 0.159 = [NH3]² / [N2] [H2]³
<em>Where [] are the equilibrium concentrations.</em>
The initial concentrations of the reactants is:
N2 = 1.00mol / 2.00L = 0.500M
H2 = 3.00mol / 2.00L = 1.50M
When the equilibrium is reached, the concentrations are:
[N2] = 0.500M - X
[H2] = 1.50M - 3X
[NH3] = 2X
<em>Where X is reaction quotient</em>
Replacing in the Kc equation:
0.159 = [2X]² / [0.500 - X] [1.50 - 3X]³
0.159 = 4X² / 1.6875 - 13.5 X + 40.5 X² - 54 X³ + 27 X⁴
0.268313 - 2.1465 X + 6.4395 X² - 8.586 X³ + 4.293 X⁴ = 4X²
0.268313 - 2.1465 X + 2.4395 X² - 8.586 X³ + 4.293 X⁴ = 0
Solving for X:
X = 0.1367. Right solution.
X = 1.8286. False solution. Produce negative concentrations
Replacing:
[N2] = 0.500M - 0.1367M
[H2] = 1.50M - 3*0.1367M
[NH3] = 2*0.1367M
The equilibrium concentrations are:
<h3>[N2] = 0.3633M</h3><h3>[H2] = 1.090M</h3><h3>[NH3] = 0.2734M</h3>
Answer
A. Its volume is decreased
Explanation
If we compress a gas (decrease) without changing its temperature, the average kinetic energy of the gas particles remains the same.
At a constant temperature, the kinetic energy of particles remains the same. If the volume is reduced at a constant temperature, then the number of particles in unit volume or area increases. If there is an increased number of particles in the unit area then it increases the frequency of collisions per unit area.
At constant temperature, the smaller the volume of the container, the larger the pressure.
Answer:
The difference is 293.15 Kelvin.
Explanation:
Given data:
Temperature difference of matter = 20°C
Temperature difference of matter in kelvin = ?
Solution;
Formula:
0°C +273.15
now we will put the values instead of 0.
20°C + 273.15 = 293.15 K
Thus, the temperature difference between two sample is 293.15 K.
