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kolbaska11 [484]
3 years ago
9

Helpppppp!!!!! It’s due today URGENT!!!!!

Chemistry
1 answer:
VladimirAG [237]3 years ago
5 0

Answer:

Explanation:

2. a [CO3 2-][H3O+] / [H2O][HCO3-

b. [H2PO4-][H3O+]/[H3PO4][H2O]

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4 years ago
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PLEASE HELP ASAP
Xelga [282]

Answer:

Explanation:According to the law of conservation of mass (mass remains the same throughout a reaction), mass is conserved in this case. This can be proven by comparing the weight of two enclosed glass containers of the reaction. They will most likely have the same weight because the products the chemical reaction creates would most likely produce a gas that can be trapped if there is no opening in the glass container. To further investigate, compare the weights of the products of the reaction with an enclosed container to another container with no lid of the same reaction.

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3 years ago
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a weather balloon is filled with 200L of helium at 27 degree Celsius and 0.950 atm. What would be the volume of the gas at -10 d
Charra [1.4K]

<u>Answer:</u> The volume when the pressure and temperature has changed is 1332.53 L

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=0.950atm\\V_1=200L\\T_1=27^oC=[273+27]K=300K\\P_2=0.125atm\\V_2=?L\\T_2=-10^oC=[273-10]K=263K

Putting values in above equation, we get:

\frac{0.950atm\times 200L}{300K}=\frac{0.125\times V_2}{263K}\\\\V_2=1332.53L

Hence, the volume when the pressure and temperature has changed is 1332.53 L

5 0
3 years ago
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