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jasenka [17]
2 years ago
5

During fission, _____. protons collide to create uranium-235 new elements are created when uranium breaks apart hydrogen atoms a

re fused together to create helium helium atoms are fused together to create hydrogen
Chemistry
2 answers:
tresset_1 [31]2 years ago
7 0
The correct answer is the second option. During fission, new elements are created when uranium breaks apart. This takes place in any of the heavy nuclei after capture of a neutron. This is the opposite of nuclear fusion. In this case, nuclei are broken down into two.
masya89 [10]2 years ago
5 0

Answer:

B. new elements are created when uranium breaks apart

Explanation:

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9. You have a mini bottle of pure maple syrup. The full container has a mass of 137
cupoosta [38]

Answer:

A

Explanation:EDGE

7 0
3 years ago
Are all mutation effects the same? Provide examples.
otez555 [7]
No. insertions add a nucleotide, deletions delete a nucleotide sequence.
3 0
2 years ago
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A mixture contains NaHCO3 together with unreactive components. A 1.75 g sample of the mixture reacts with HA to produce 0.561 g
Lynna [10]

Answer:

\%NaHCO_3=61.2\%

Explanation:

Hello.

In this case, since the undergoing chemical reaction is only between the sodium bicarbonate and the acid HA:

NaHCO_3+HA\rightarrow NaA+H_2O+CO_2

For 0.561 g of yielded carbon dioxide (molar mass 44 g/mol), the following mass of sodium bicarbonate (molar mass 84 g/mol) that reacted was:

m_{NaHCO_3}=0.561gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molNaHCO_3}{1molCO_2} *\frac{84gNaHCO_3}{1molNaHCO_3} \\\\m_{NaHCO_3}=1.071g

Considering the 1:1 mole ratio between CO2 and NaHCO3. Finally, the percent by mass of NaHCO3 is computed by dividing the mass of reacted NaHCO3 and t the mixture:

\%NaHCO_3=\frac{1.071g}{1.75g}*100\%\\ \\\%NaHCO_3=61.2\%

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5 0
3 years ago
The formula of heavy water​
Crazy boy [7]

the formula of the heavy water is D2O

8 0
2 years ago
What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3
konstantin123 [22]
First we will calculate the number of moles of Iron:
n =  \frac{m}{M}
, where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
n= \frac{84.9}{55.845} = 1,52 moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So 1,52= \frac{mOxygen}{32} where 32 is the Atomical Weight of Oxygen (16 x 2).
=>mOxygen=32*1,52=48,64g
6 0
2 years ago
Read 2 more answers
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