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3 years ago

What is the molar mass of sulfur (S)?

Chemistry

2 answers:

gtnhenbr [62]3 years ago

8 0

Answer:

32.065 g/mol

Explanation:

Or 32.06 for AP3X

mars1129 [50]3 years ago

4 0

Answer:

32.075 u

Explanation:

Atomic number-16

Symbol (S)

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A grade 8 students burnt white phosphorus in the air contained in a bell jar. what will be the volume of the renaming air in the

jok3333 [9.3K]

Try d cuz if im not mistaken if you burnt white phosphorus all the gas is going to take most the air

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2 years ago

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For alpha decay to cause a loss in mass, such as that in the uranium 238 conversion to thorium 234, what must the atomic weight

Aleonysh [2.5K]

Explanation:

Reaction equation showing alpha decay in Uranium-238 is as follows.

$^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He$

It is known that an alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons.

Symbol of an alpha particle is $^{4}_{2}\alpha$ .

As atomic mass or weight is the sum of total number of protons and neutrons present in an atom.

Hence, the atomic weight of the alpha particle is (2 + 2) = 4.

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3 years ago

Mass defect for oxygen-16 = 0. 13261 amu How many kilograms does the mass defect represent? 1. 66 × 10-27 kg 2. 20 × 10 -28 kg 3

Zepler [3.9K]

Mass defect for oxygen-16 = 0. 13261 amu, in the kilograms the mass defect equals to 2.20 × 10⁻²⁸ kg.

<h3>What is mass defect?</h3>

Mass defect is the difference between the mass of of an whole atom and the combined mass of its individual particles present in that atom.

We know that, 1 amu = 1.6 × 10⁻²⁷ kg

Given that, mass defect for oxygen-16 = 0.13261 amu

To calculate this defect in terms of kilograms, we have to convert into kg unit as:

0.13261 amu = 0.13261 amu × 1.6 × 10⁻²⁷ kg/amu

0.13261 amu = 2.20 × 10⁻²⁸ kg

Hence option (2) is correct.

To know more about Mass defect, visit the below link:

brainly.com/question/4334375

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2 years ago

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree

lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = $T_1=33.9^oC=33.9+273K=306.9 K$

Final temperature of the water = $T_2$

Specific heat capacity of water under these conditions = c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

$Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)$

$-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC$

The new temperature of the water bath 32.0°C.

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4 years ago

How does increasing the temperature affect collisions?

ddd [48]

Combustion Have a great day!

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3 years ago

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