The molarity of the Isopropanol solution is 1.68 M.
<h3>How we calculate molarity?</h3>
Molarity of any solution can be calculated as:
M = n/V, where
n = no. of moles
V = volume = 1,250mL = 1.250L
For this first we have to calculate the moles of Isopropanol (C₃H₈O), and it can be calculated as:
n = W/M, where
W = mass of C₃H₈O = 127 grams
M = molar mass of C₃H₈O = 60.1 g/mol
Moles of C₃H₈O = 127g / 60.1 g/mol = 2.1 moles
Now, we calculate the molarity of solution by using the above formula and by putting values as:
M = 2.1/1.250 = 1.68 M
Hence, 1.68 M is the molarity of the solution.
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