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ziro4ka [17]
3 years ago
11

Why do so many of the people of India live in the Ganges River Valley?

Physics
2 answers:
bearhunter [10]3 years ago
7 0
1 for the river with the farming
irga5000 [103]3 years ago
5 0
The river provides fertile soil for farming
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The number of magnetic field force lines passing through the given surface determines: 1. magnetic flux 2. magnetic induction 3.
Assoli18 [71]
A magnetic flux would be the correct answer

8 0
3 years ago
What is the average velocity of the time interval 0 to 4 seconds
Anvisha [2.4K]
Average velocity over a given time interval is the distance traveled divided by the time:
v= \frac{60m-20m}{4s-0s} =40/4=10 \frac{m}{s} 
7 0
4 years ago
If a weightlifter lifts a 286 kg mass 0.25 meters above his head, how much PEg does the mass have?
vazorg [7]

Answer:

Change in potential energy is 700.7 J.

Explanation:

Given:

Mass of the object is, m=286 kg

Height to which the object is raised above his head, h=0.25 m

Acceleration due to gravity is, g=9.8 m/s²

We know that for a mass m raised to a height h, the change in potential energy is given as:

\Delta PE=mgh, where, \Delta PE\rightarrow \textrm{Change in Potential Energy}

Now, plug in the given values and solve.

\Delta PE=286\times 9.8\times 0.25=700.7\textrm{ J}

Therefore, the change in the potential energy is 700.7 J.

3 0
4 years ago
Read 2 more answers
In a particular run of the “Archimedes principle” experiment a particular unknown substance is found to have a “dry mass” of 4.5
iris [78.8K]

Answer:

D = 18000 kg/m3

V = 2.5*10{-7}m3

Explanation:

From the Archimedes principle,

Weight of fluid displaced = W_{air} - W_{water}

W_{air} = 4.5 gm

W_{water} = 4.25 gm

W = [4.5 - 4.25]*9.81*10^{-3}

W = 2.4525*10{-3} N

\frac{density\ of\ object}{density\ of\ fluid} = \frac{weight\ in\ air}{weight\ of\ displaced\ fluid}

Density\ of\ object = \frac{D_{water}*Weight\ in\ air}{weight\ of\ displaced\ water}

D = \frac{1000*4.5*10^{-3}*9.8}{2.4525*10^{-3}}N

D = 18000 kg/m3

b) object Volume can be obtained  as ,

V = \frac{m}{D} = \frac{4.5*10^{-3}}{18000}

V = 2.5*10{-7}m3

7 0
3 years ago
Capacitances of 10uF and 20uF are connected in parallel,
jarptica [38.1K]

Answer:

The equivalent capacitance will be 15\mu F  

Explanation:

We have given two capacitance C_=10\mu F\ and\ C_2=20\mu F

They are connected in parallel

So equivalent capacitance C=C_1+C_2=10+20=30\mu F

This equivalent capacitance is now connected in series with 30\mu F

In series combination of capacitors the equivalent capacitance is given by \frac{1}{C}=\frac{1}{30}+\frac{1}{30}

C=\frac{30}{2}=15\mu F

So the equivalent capacitance will be 15\mu F  

5 0
3 years ago
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