Alpha emission is the process results in a change in mass number. Option B is correct.
<h3>What is mass number?</h3>
The total number of protons and neutrons in an atomic nucleus is known as the mass number, often known as the atomic mass number or nucleon number.
It's about the same as the atom's atomic mass, expressed in atomic mass units.
The alpha particle is a helium nucleus with two protons and two neutrons in an alpha decay or alpha emission. The number of protons and neutrons is reduced by two as a result of this action.
The quantity of protons and neutrons is affected by gamma emission descent. Also, while electron capture has no effect on the number of neutrons, it does raise the 1 also number of protons by one.
Alpha emission is the process results in a change in mass number.
Hence option B is correct.
To learn more about the mass number, refer:
brainly.com/question/4408975
#SPJ1
Yolanda might put more items to the desk to make it heavier, requiring more force.
We need to learn more about the force acting on an object in order to locate the solution.
<h3>How can the force that is required to modify the motion be increased?</h3>
- We are aware that the word for force is,
F=ma
where m denotes the object's mass and an its acceleration
- There are two ways to increase the force required to alter the motion of the table.
- One is to increase the mass, and the other is to accelerate it more quickly.
- Otherwise, there will be a lot of friction between the surfaces, making it difficult to move without exerting a lot of force.
We can infer from this that Yolanda could add items to the desk to increase its mass, necessitating the use of additional force.
Learn more about the force here:
brainly.com/question/4075805
#SPJ1
Do you mean ‘Does a larger object have less attraction than a smaller object?’ If so, then the answer is objects with a larger mass exert more attraction while objects with a smaller mass have less attraction.
Answer:
<em>6.77m/s</em>
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the velocities before collision
v is the final collision
Given
m1 = 300g = 0.3kg
u1 = 6.0m/s
m2 = 10g = 0.01kg
u2 = 30m/s
Required
The bird's speed immediately after swallowing v
Substitute the given values into the formula
m1u1 + m2u2 = (m1+m2)v
0.3(6) + 0.01(30) = (0.3+0.01)v
1.8+0.3 = 0.31v
2.1 = 0.31v
v = 2.1/0.31
<em>v = 6.77m/s</em>
<em>Hence the bird's speed immediately after swallowing is 6.77m/s</em>
