Q: An appliance with a 20 Ω resistor has a power rating of 15.0 W. Find the maximum current which can flow safely through the appliance g
Answer:
0.866 A
Explanation:
From the question,
P = I²R............................. Equation 1
Where P = power, I = maximum current, R = Resistance.
Make I the subject of the equation
I = √(P/R).................... Equation 2
Given: P = 15 W, R = 20 Ω
Substitute these values into equation 2
I = √(15/20)
I = √(0.75)
I = 0.866 A
Hence the maximum current that can flow safely through the appliance = 0.866 A
Explanation:
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Answer:
Explanation:
We know that impedance of a RLC circuit is given by 
So 
here R is resistance 
is inductive reactance and 
is capacitive reactance
To minimize the impedance 
should be zero we know that 
So 
We know that 
So 
Where f is resonance frequency
