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Amanda [17]
3 years ago
15

Racionalize o denominador da equação abaixo: 5 + 3 ²√5 / ²√5

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0
I hope this helps

\cfrac{5+3 \sqrt{5} }{ \sqrt{5} } =\cfrac{(5+3 \sqrt{5}) \sqrt{5}  }{ \sqrt{5}* \sqrt{5}  }= \cfrac{5 \sqrt{5}+15 }{5}  = \cfrac{5 (\sqrt{5}+3) }{5}  = \sqrt{5}+3
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Identify the monomial function described as odd or even, and indicate whether a is positive or negative.
Igoryamba

Answer:

Case 1: As x > 0 increases, f(x) increases.  As x < 0 decreases, f(x) decreases.

It is an 'odd' function with 'positive' a.

Case 2: As x > 0 increases, f(x) decreases.  As x < 0 decreases, f(x) decreases.

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Case 3: As x > 0 increases, f(x) increases.  As x < 0 decreases, f(x) increases.

It is an 'even' function with 'positive' a.

Case 4: As x > 0 increases, f(x) decreases.  As x < 0 decreases, f(x) increases.

It is an 'odd' function with 'negative' a.

Step-by-step explanation:

Let us consider a monomial function:

             f(x) = axⁿ

Case 1:

As x > 0 increases, f(x) increases.  As x < 0 decreases, f(x) decreases.

This happens only if a is 'positive' and n is 'odd'.  So, it is an 'odd' function with 'positive' a.

Case 2:

As x > 0 increases, f(x) decreases.  As x < 0 decreases, f(x) decreases.

This happens only if a is 'negative' and n is 'even'. So, it is an 'even' function with 'negative' a.

Case 3:

As x > 0 increases, f(x) increases.  As x < 0 decreases, f(x) increases.

This happens only if a is 'positive' and n is 'even'. So, it is an 'even' function with 'positive' a.

Case 4:

As x > 0 increases, f(x) decreases.  As x < 0 decreases, f(x) increases.

This happens only if a is 'negative' and n is 'odd'. So, it is an 'odd' function with 'negative' a.

Keywords: monomial function, odd function, even function

Learn more about monomial function from brainly.com/question/8973176

#learnwithBrainly

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3 years ago
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Answer:

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Each element of A has unique value in set B.

By definition of  function

In given function

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Substitute x=0

y=\pm \sqrt{0+2}=\pm \sqrt 2

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Answer:

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