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Crank
3 years ago
12

A(3-x)=-2x+B if x=2 How do I find A and B what are the answers

Mathematics
1 answer:
irina1246 [14]3 years ago
4 0

Answer:

A=5,B=9\\\\or\ A=-9,B=-5

Step-by-step explanation:

A(3-x)=-2x+B\\\\Given\ x=2\\\\Substitute\ the\ value\ of\ x\\\\A(3-2)=-2\times 2+B\\\\A=-4+B\\\\A=B-4\\\\So\ the\ value\ of\ A\ is\ 4\ less\ than\ the\ value\ of\ B.\\\\When\ B=9\Rightarrow A=9-4=5\\\\When\ B=-5\Rightarrow B=-5-4=-9\\\\Hence\ A=5,B=9\\\\or\ A=-9,B=-5

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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
you deposit 1000 in savings account that earns .5% each month assuming you do not deposit or withdraw any money from the account
ikadub [295]

Answer:

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Step-by-step explanation:

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Step 1: Plug in known variables

A = 1000(1 + 0.005/12)^36

Step 2: Multiply it all together

1000(1.00042)^36

1000(1.01511)

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7 0
3 years ago
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olga_2 [115]

Answer:

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Step 2: Divide both sides by -1.

−x

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5 0
3 years ago
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3 0
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Answer:

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4 0
3 years ago
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