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mel-nik [20]
3 years ago
13

What is 800-5x divided by 6.5

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:10 over 13 x

Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2

to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13

factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)

for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x

solution: 800-10 over 13x so your answer would still be

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2) Ten Percent of 27 is _<br> One Percent of 27 is<br> Find 14% of 27.
geniusboy [140]

Step-by-step explanation:

10%of 27

=  \frac{10}{100}  \times 27

=  \frac{27}{10}  = 2.7

1% of 27

=  \frac{1}{100}  \times 27 = 0.27

14\%of \: 27 =  \frac{14}{100}  \times 27 = 3.78

8 0
3 years ago
Grade 7 math extra credit
Nonamiya [84]
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1/3 * 2400 = 2400/3 = 800
leaving 2400 - 800 = 1600

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3 0
3 years ago
(x-5)1/2+5=2<br> (x-5)1/2=-3<br> [(x-5)^1/2]^2=(-3)^2
Studentka2010 [4]

Answer:

x = 14

Step-by-step explanation:

You want to solve for x, right?

(x-5)^(1/2)+5=2

You have it right so far.

(x - 5)^(1/2) = -3

(x - 5)  =  (-3)^2

x - 5 = 9

x = 9 + 5 = 14

3 0
3 years ago
Solve 3(4m - 6) = 12 and explain each step
Studentka2010 [4]
Distribute the 3 to 4m and 6. this makes 12m-18=12
now add 18 to both sides.
12m=30
now divide by 12
m=30/12
3 0
3 years ago
Solve the system using elimination.<br><br> 2x + 3y = 17<br> x + 5y = 19
ale4655 [162]

\left\{\begin{array}{ccc}2x+3y=17\\x+5y=19&|\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+3y=17\\-2x-10y=-38\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad-7y=-21\qquad\text{divide both sides by (-7)}\\.\qquad\qquad \boxed{y=3}\\\\\\\text{Substitute the value of y to the second equation}\\\\x+5(3)=19\\\\x=15=19\qquad\text{subtract 15 from both sides}\\\\\boxed{x=4}\\\\Answer:\ x=4\ and\ y=3.

5 0
3 years ago
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