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3 years ago

What is 800-5x divided by 6.5

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

Answer:10 over 13 x

Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2

to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13

factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)

for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x

solution: 800-10 over 13x so your answer would still be

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3 years ago

How to do the problem

MrMuchimi

Order of operations are:
1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
4. Addition and Subtraction (from left to right)

So, on your first one:
Parentheses first:
8(3+4)-2*8/(5-3)
8(7)-2*8/(2)

There are no exponents so multiplication and division:
56-16/2
56-8

Finally, addition and subtraction:
56-8=48

Your second problem is a bit more complicated but follows the same rules:
 $( 8^{2}+(13-4) ^{2} )/5$

Parentheses first:
 $( 8^{2}+ 9^{2})/5)$

Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5

Now back to parentheses:
(145)/5

Division:
145/5=29

Hope that helps

8 0

3 years ago