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mel-nik [20]
3 years ago
13

What is 800-5x divided by 6.5

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:10 over 13 x

Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2

to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13

factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)

for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x

solution: 800-10 over 13x so your answer would still be

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<u>Step-by-step explanation:</u>

1a) -110 + 360 (one rotation clockwise) = 250°

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Quadrant III identifies that both sin (y) and cos (x) are negative.

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\tan\theta=\dfrac{y}{x}=\dfrac{\sqrt{39}}{5}              \cot\theta=\dfrac{x}{y}=\dfrac{-5}{-\sqrt{39}}  rationalized = =\dfrac{5\sqrt{39}}{39}

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