Answer:
Not necessarily. There are many ways to write a basic equation with a negative answer. For example, -3-4 = -7. Here 4 is a positive number but because you subtract 4 to 3 or take away 4 from 3 being a negative number and so you get a negative answer. Another example is 6+(-9). There are a couple of ways you can resolve this. My method is to subtract 9 from 6 which gives you 3 and simply add a negative sign.
Let me know if you'd like more examples. Hope this helps!! Sorry if it is confusing I can explain you in a more simpler way if you'd like.
Step-by-step explanation:
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
39
Step-by-step explanation:
using line and triangle property you can solve this question
Answer:
The correct option is (b).
Step-by-step explanation:
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
Answer:
https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/dot-plot/v/frequency-tables-and-dot-plots
Step-by-step explanation: