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marshall27 [118]
4 years ago
10

Which is greater 6/12 or 1/3

Mathematics
1 answer:
Inessa [10]4 years ago
5 0

Answer:

1/3 is bigger

Step-by-step explanation:

6/12 might look bigger but its not

    PLEASE MARK AS BRAINLIEST

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Solve for x: x2-14x+49
Bezzdna [24]

Answer:

x2 − 14x + 49 = 0

Step-by-step explanation:


8 0
3 years ago
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Demetri is trying to determine which of the two loans would be better.
Ulleksa [173]

Answer:

Discrete

Step-by-step explanation:

Since interest is not added all the time but only a set number of times a year both loans would be best modeled by a discrete relationship.

4 0
3 years ago
Given B=45°, C=105°, and a=8, find the exact value of b in triangle ABC
Veronika [31]

Answer:

hope the screenshot will help

Step-by-step explanation:

7 0
3 years ago
Sleep apnea is a disorder in which there are pauses in breathing during sleep. People with this condition must wake up frequentl
Pachacha [2.7K]

Answer:

a) 0.24356 or 24.36%

b) [102.39 , 105.61]

c) The interpretation of this confidence interval is that in samples of 427 people aged 65 years and older, there is a 99% probability that the number of people that suffers sleep apnea is between 103 and 105.

Step-by-step explanation:

a)

This can be considered a binomial distribution (a person either has sleep apnea or not).

Based on the sample we have the probability of suffering the condition is  

p = 104/427 = 0.24356  

and q (the probability of not suffering the condition) is  

q=1-0.24356=0.75644

So the proportion of people aged 65 years and older who have sleep apnea is 0.24356 or 24.36%

b)

To check if we can <em>approximate this binomial distribution with the Normal distribution</em> we must see that

np ≥ 5 and nq ≥ 5

where n is the sample size. Since

427*0.24356 ≥ 5 and 427*0.75644 ≥ 5  

we can approximate the binomial with a Normal distribution with mean  

np = 427*0.24356 = 104  

and standard deviation  

\large s=\sqrt{npq}=\sqrt{427*0.24356*0.75644}=8.867

The 99% confidence interval (without the continuity correction factor) is given by the interval

\large [\bar x-z^*\frac{s}{\sqrt n}, \bar x+z^*\frac{s}{\sqrt n}]

where

\large \bar x <em>is the sample mean  </em>

<em>s is the sample standard deviation  </em>

<em>n is the sample size </em>

\large z^* <em>is the 0.01 (99%) upper critical value for </em>

<em>the Normal distribution N(0;1). </em>

The value of \large z^* can be found either by using a table or a computer to find it equals to  

\large z^*=2.576

and our 99% confidence interval <em>(without continuity correction) </em>is

\large [104-2.576*\frac{8.867}{\sqrt{427}}, 104+2.576*\frac{8.867}{\sqrt {427}}]=[102.8946,105.1054]

We can now introduce the continuity correction factor. This should be done because <em>we are approximating a discrete distribution (Binomial) with a continuous one (Normal). </em>

This is simply done by widening the interval in 0.5 at each end, so our final 99% confidence interval is

[102.3946 , 105.6054] = [102.39 , 105.61] rounded to 2 decimal places.

c)

The interpretation of this confidence interval is that in samples of 427 people aged 65 years and older, there is a 99% probability that the number of people that suffers sleep apnea is between 103 and 105.

If another study found a 15% of elderly people suffered sleep apnea, that would mean that in a sample of 427 only 64 would have the condition. Since that number is less than 103 by far, that would give us a reason to doubt about the conditions that framed the study (sample size, sampling method, age of people, etc.)

4 0
3 years ago
During a recent rainstorm, 888 centimeters of rain fell in Dubaku's hometown, and 2.362.362, point, 36 centimeters of rain fell
grigory [225]

Answer:

The question is re-framed:

During a recent rainstorm,8 centimeters of rain fell in Dubaku's hometown, and 2 point,36 centimeters of rain fell in Elliot's hometown. During the same storm, 15 point, 19 centimeters of snow fell in Alperen's hometown. How much more rain fell in Dubaku's town than in Elliot's town? In centimeters.

Rain fall on Dubaku's town is 8-(2.36)=5.64\ cm more than of Elliots's town.

Step-by-step explanation:

Rainfall on Dubaku's hometown on the day of the rain storm =8\ cm

Rainfall on Elliots's hometown on the day of the rain storm =2.36\ cm

How much more rain fell in Dubaku's town = Difference of the rainfall on Dubaku's and Elliots's hometown.

So the difference =(8)-(2.36)=5.64\ centimeters.

Our final answer =5.54 centimeters.

3 0
3 years ago
Read 2 more answers
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