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pshichka [43]
3 years ago
10

Ruby has 4 feet of rope that she wants to cut into 5 equal-sized pieces

Mathematics
2 answers:
Sonbull [250]3 years ago
5 0

Answer:

Each length of the rope will be 0.8 feet long

vekshin13 years ago
5 0

Answer:

Each piece has 15 of 4 feet of rope.

Ruby has 4 feet of rope that she wants to cut into 5 equal-sized pieces.

What is true about the length of each piece of the rope?

Each piece has 15 of 4 feet of rope.

I took a screen shot that I got it correct.

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The rule for h(f(x))
Marat540 [252]

Answer:

h(f(x))=3x-4

Step-by-step explanation:

You combine both F(X) and H(x).

f(x)=x-7 , therefore  it is f(x)=1x-7

You add 2x with 1x  to get  3x

and 7-3 is -4.

h(f(x))=3x-4

7 0
3 years ago
What is the first quartile of this data set? {6, 47, 49, 15, 43, 41, 7, 36}
stepladder [879]
<span>The first quartile is the same as the median of the data which are less than the overall median. Same as the 25th percentile.
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I hope my answer has come to your help. God bless and have a nice day ahead!
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3 years ago
1<br> 3<br> 4<br> 0.5<br> - 3<br> - 6.5<br> - 10<br> What is the linear function?
Wewaii [24]

Answer: it’s probably negative 6.5 but there has to be a grid to be more clear

Step-by-step explanation:

7 0
3 years ago
I have a past due balance of $87.50 and my new charges are $75.00. I was also charged a late fee of 15% of my past due balance.
Kitty [74]
Past due balance = $87.50
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8 0
3 years ago
Read 2 more answers
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
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