The ratio of girls to boys competing at a gymnastics competition was 2 to 1 there were 75 kids participating in the competition.
1 answer:
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Answer:
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs. Notice that:
In this case you have the following expression given in the exercise:
Where the variable is "j".
When you multiply signs, you get:
Now you need to identify that like terms and then you need to add them (or combine them). So, applying this procedure you get that the simplified form of the expression is the shown below:
As you can observe, you get a 2nd degree binomial.
Answer:
51%
Step-by-step explanation:
Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.
<h3>Probability relations</h3>We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).
The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:
42% +9% = 51%
The probability of passing one or the other is 51%.
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<em>Additional comment</em>
We can also get there using the relation ...
P(A+B) = P(A) +P(B) -P(AB)
The union of A and B also includes their overlap:
P(A+B) = P(AB') +P(A'B) +P(AB)
In other words, the probability of interest is ...
P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)
P(AB') +P(A'B) = 51%
