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Sav [38]
3 years ago
6

The cochlea is a liquid-filled cavity in the inner ear. T or F?

Physics
2 answers:
azamat3 years ago
7 0
True the fluid in  it helps vibrate and produce the sound so that we can hear things
lutik1710 [3]3 years ago
5 0
Yes. It is the organ for hearing. <span>The cochlea and the semicircular canals are filled with a water-like fluid.</span>
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Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a larg
valentina_108 [34]

Answer:

-time it takes for the sled to come to a stop after launch of rocket = 7.244 s

-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m

Explanation:

From the question, looking at the motion while accelerating, we have;

Initial velocity; u = 0 m/s

Acceleration; a = 13.5 m/s²

Time; t = 3.3 s

Let's use first equation of motion to find final velocity (v).

v = u + at

v = 0 + (13.5 × 3.3)

v = 44.55 m/s

In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.

d1 = ut + ½at²

d1 = 0(3.3) + ½(13.5 × 3.3²)

d1 = 73.5075 m

Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².

Thus, from v = u + at, we can find the time it take for the sled to come to a stop.

Now, since it's coming to rest acceleration will be negative. Thus;

0 = 44.55 + (-6.15t)

0 = 44.55 - 6.15t

t = 44.55/6.15

t = 7.244 s

Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.

Thus, we'll use the equation;

v² = u² + 2as

Where s will be the second displacement which we will call d2.

Thus;

0² = 44.55² + (-2 × 6.15 × s)

0 = 1984.7025 - 12.3s

12.3s = 1984.7025

s = 1984.7025/12.3

s = 161.358

Thus, d2 = s = 161.358 m

Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;

= d1 + d2 = 73.5075 + 161.358 = 234.8655 m

4 0
4 years ago
A football (450 g) falls vertically from rest onto the ground from a height of 5.0 m. If the force that
mario62 [17]
I don’t understand sorry
5 0
3 years ago
A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If
katrin2010 [14]

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. If the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. If after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 4.0 rad/s, find the average angular acceleration that the disk experiences. (Assume the positive direction is in the initial direction of rotation of the disk. Indicate the direction with the sign of your answer.)

Assume after 35 s of contact with this spinning rubber wheel, the disk has an angular velocity of 11.0 rad/s.

Answer:

385 rad

Explanation:

The expression for the angular acceleration of a disk that is in contact with a spinning wheel can be given as:

\alpha = \frac{\delta \omega}{\delta t}

where \delta\omega = \omega_f - \omega_i

\alpha = \frac{ \omega_f-\omega_i}{\delta t}

\alpha = \frac{ 4.0 rad/s-0 rad/s}{35}

\alpha =0.14 rad/s^2

Angular displacement of a disk can be calculated by using the formula:

\theta = \omega t

substituting 11.0 rad/s for \omega and t = 35 s ; we have:

\theta = 11.0 rad/s * 35 s

\theta = 385 rad

4 0
3 years ago
Read 2 more answers
Electrons in an x-ray tube are accelerated through 144 kV and directed toward a target to produce x-rays. Calculate the power of
Katarina [22]

Answer:

Power of the electron beam in the x-ray tube is 2304 W

Explanation:

Given;

voltage of the electron beam in the x-ray tube, V =  144 kV = 144 x 10³ V

current of the electron beam in the x-ray tube, I = 16.0 mA = 16 x 10⁻³ A

Power is given as the product of voltage and current in a circuit.

Power of the electron beam in the x-ray tube, P = V x I

Power of the electron beam in the x-ray tube, P = 144 x 10³ V x 16 x 10⁻³ A

P = 2304 W

Therefore, power of the electron beam in the x-ray tube is 2304 W

7 0
3 years ago
A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball
lora16 [44]

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = 50.4 m/s

Final speed of the ball, v = -37 m/s (As it returns)  

(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

J=m(v-u)

J=0.06\times (-37-(50.4))  

J = -5.24 kg-m/s

(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)

W = -35.1348 Joules

Hence, this is the required solution.

6 0
3 years ago
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