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Lady bird [3.3K]
3 years ago
15

A roller coaster has a mass of 250 kg,

Physics
1 answer:
N76 [4]3 years ago
6 0
Potential Energy = mass x gravity x height
PE = mgh
PE = 250kg x 9.8 m/s^2 x 50m
PE = 118,750 joules = 118kJ
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Explanation:

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I know this is easy but i’m am just not sure
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kinetic energy

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Which wave has a disturbance that is parallel to the wave motion?
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If a data point is way off the trend line, what will not resolve the problem?
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A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder
QveST [7]

Answer:

\Delta \theta = 47.57^{\circ} C

Explanation:

given,

moles of air compressed, n = 1.70 mol

initial temperature, T₁ = 390 K

Power supply by the compressor, P = 7.5 kW

Heat removed = 1.3 kW

Angular frequency of the compressor, f = 110 rpm = 110/60 = 1.833 rps.

Time of compression = time of the hay revolution

             =\dfrac{1}{2}\ T

             =\dfrac{1}{2}\times \dfrac{1}{f}

             =\dfrac{1}{2}\times \dfrac{1}{1.833}

             =0.273 s

Using first law of thermodynamics

U = Q - W

now,

\dfrac{\Delta U}{\Delta t} = \dfrac{\Delta Q}{\Delta t}- \dfrac{\Delta W}{\Delta t}

Power supplied \dfrac{\Delta W}{\Delta t} = 7.5 kW

heat removed \dfrac{\Delta Q}{\Delta t} = 1.3 kW

now,

\dfrac{\Delta U}{\Delta t} = 7.5 -1.3

\dfrac{\Delta U}{\Delta t} = 6.2 kW

we know,

\dfrac{\Delta U}{\Delta t}=\dfrac{nC_v\Delta \theta}{\Delta t}

 C_v for air = 5 cal/° mol

                   = 5 x 4.186 J/mol°C  = 20.93 J/mol°C

now,

\Delta \theta = \dfrac{\Delta U}{\Deta t}\times \dfrac{\Delta t}{n C_v}

\Delta \theta = 6.2\times 10^3 \times \dfrac{0.273}{1.7\times 20.93}

\Delta \theta = 47.57^{\circ} C

the temperature change per compression stroke is equal to 47.57°C.

4 0
3 years ago
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