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timurjin [86]
4 years ago
13

When seen from an airplane, a rainbow sometimes forms a complete circle. When this happens, the plane's shadow is a. in the cent

er of the rainbow. b. totally outside the rainbow. c. in the upper part of the rainbow. d. Nowhere. There is no shadow. e. in the lower part of the rainbow.
Physics
1 answer:
ValentinkaMS [17]4 years ago
6 0

Answer:

A. in the center of the rainbow

Explanation:

A rainbow is always seen half circle

For one to see the full circle of the rain bow, it will appear that the shadow of the object will be found in the centre of the rain bow.

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A 1.5kg cannon is loaded with a 0.52 kg ball . The cannon is ignited and launches the ball forward with speed of 75m/s. Determin
Mila [183]

Answer:

-26 m/s (backward)

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum momentum of the cannon + ball system must be conserved before and after the explosion.

Before the explosion, they are both at rest, so the total momentum is zero:

p = 0

After the explosion, the total momentum is:

p=MV+mv

where

M = 1.5 kg is the mass of the cannon

m = 0.52 kg is the mass of the ball

v = +75 m/s is the velocity of the ball

V is the velocity of the cannon

Since the momentum is conserved, we can equate the two expressions:

0=MV+mv

And solving, we find V:

V=-\frac{mv}{M}=-\frac{(0.52)(+75)}{1.5}=-26 m/s

where the negative sign means the direction is opposite to that of the ball.

4 0
4 years ago
A 40kg rock falls off a cliff that is 50 meters high. How fast is the speed of the rock when it hits the ground.
olga2289 [7]

Answer:

huh?

Explanation:

6 0
4 years ago
Read 2 more answers
A 2kg mass is moving at 3m/s. What is its kinetic energy?
Romashka [77]

Explanation:

\frac{1}{2}m {v}^{2}  \\  \frac{1}{2}  \times  2 \times  {3}^{2}  \\ 1 \times 9 = 9j

8 0
2 years ago
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A firecracker sitting on the ground explodes into two pieces. Immediately after the explosion, one of the pieces has momentum of
Misha Larkins [42]

Answer:

other part will move with momentum 0.5 kg m/s towards west

Explanation:

As we know that the during the explosion event the time interval is very small and there is no impulsive force on the firecracker during this time

so here we can say that the momentum will remains conserved during the this event

now if the initial momentum of the firecracker is zero

then the final momentum must be zero

so here we can say

P_1 + P_2 = 0

P_1 = 0.5 kg m/s towards east

now from above equation

P_2 = - P_1 = -0.5 kg m/s

so the other part will move with momentum 0.5 kg m/s towards west

6 0
4 years ago
The ability to distinguish between acceleration and velocity will be critical to your understanding of many other concepts in th
Sauron [17]

Answer:

Object could only be moving with increasing speed.

Explanation:

Let us consider the general formula of acceleration:

a = (Vf - Vi)/t

Vf = Vi + at   -------- equation 1

where,

Vf = Final Velocity

Vi = Initial Velocity

a = acceleration

t = time

<u>FOR POSITIVE ACCELERATION:</u>

Vf = Vi + at

since, both acceleration and time are positive quantities. Hence, it means that the final velocity of the object shall be greater than the initial velocity of the object.

Vf > Vi

It clearly shows that if an object moves with positive acceleration. <u>It could only be moving with increasing speed.</u>

Solving the same equation for negative acceleration shows that the final velocity will be less than initial velocity and object will be moving with decreasing speed.

And for the constant velocity final and initial velocities are equal and thus, acceleration will be zero.

7 0
3 years ago
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