Answer:
D. 8ab+12a-2b-3
Step-by-step explanation:
You are basically combining like terms
Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so
![z^{2}=\frac{Ak}{Aj}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7BAk%7D%7BAj%7D)
we have
![z=4](https://tex.z-dn.net/?f=z%3D4)
substitute
![4^{2}=\frac{Ak}{Aj}](https://tex.z-dn.net/?f=4%5E%7B2%7D%3D%5Cfrac%7BAk%7D%7BAj%7D)
![16=\frac{Ak}{Aj}](https://tex.z-dn.net/?f=16%3D%5Cfrac%7BAk%7D%7BAj%7D)
![Ak=16Aj](https://tex.z-dn.net/?f=Ak%3D16Aj)
therefore
The area of triangle K is 16 times greater than the area of triangle J
Answer:
5√3
Step-by-step explanation:
Answer:
n^22 (I love your profile picture by the way)
Step-by-step explanation: