Answer:
The midpoint M is (5,7)
Step-by-step explanation:
U(8,9)
V(2,5)
m = [(8+2)/2 , (9+5)/2]
= [(10/2) , (14/2)]
= (5,7)
(Correct me if i am wrong)
Answer:
B
Step-by-step explanation:
the options A and B are the ones that make sense
to get rid of one of the options, you have to substitute.
lets try 6
5+ 3.5(6)= 5+21= 26
3+ 4(6)= 3+24 = 27
in that example, the Bowling Pin is the best deal for Tina
Answer:
<h2>3(cos 336 + i sin 336)</h2>
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336)
Mean = 62 in
SD = 2 in
At 16% = 0.16 and using Z tables,
Z≈ -0.99
x =(-0.99*2) + 62 ≈ 60 in
This represents jockeys who are shorter than 60 in.
Answer:
8 π .
Step-by-step explanation:
radius increases at a constant rate of 1 in/sec.
dr / dt = 1
where r is radius .
radius after 4 sec
r = 1 x 4 = 4 in
area A = π r²
differentiating both sides
dA / dt = 2 π r dr / dt
Putting dr / dt = 1 , r = 4 in
dA / dt = 2 π x 4 x 1
= 8 π sq in per sec.
Area increases at the rate of 8 π per sec.
