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NARA [144]
3 years ago
12

Zoe had a board 5 1/4 feet long she cut off a piece now the board is 3 5/6 feet long how long was the piece she cut off

Mathematics
1 answer:
uysha [10]3 years ago
7 0

Least common denominator is 24

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Please help<br><br>Point____is plotted at -4/5​
musickatia [10]

Answer:

C

Step-by-step explanation:

-4/5 is -0.8, which is at point C

plz brainliestt

8 0
3 years ago
Read 2 more answers
"Ten subtracted from the quotient of a number<br> and 5 is 18."
Anika [276]

Answer: n/5 - 10 = 18: this would be the equation. Your answer would be 140.

Step-by-step explanation: Let consider the number as ‘X’

Quotient of a number and 5 can be written as

                        X divided by 5

Ten subtracted from the quotient of a number and 5 can be written as

                       (X divided by 5)-10

Ten subtracted from the quotient of a number and 5 is 18 can be written as

                       (X divided by 5)-10=18

  By solving the above equation, find ‘X’

                       (X divided by 5) = 18 + 10

                    X/5=28

                       X = 28 x 5 = 140                    

                       

                   

4 0
3 years ago
15/331<br> please show in dept steps for the division
photoshop1234 [79]

\frac{15}{331}or 0.045317

Step-by-step Explanation :

As the given fraction is an improper fraction, it is hard to divide properly. Either :

☆ You can write what it is given as per question for the answer.

☆ Else, by dividing, we will get a huge value. In this case, we get it as 0.045317

8 0
2 years ago
How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?
kakasveta [241]

This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.

Case 1: Five A's and One B

Total number of letters = 6

Total number of words possible = \frac{6!}{5!*1!}=6

Case 2: Five A's and Two B's

Total number of letters = 7

Total number of words possible = \frac{7!}{5!*2!}=21

Case 3: Five A's and Three B's

Total number of letters = 8

Total number of words possible = \frac{8!}{5!*3!}=56

Total number of possible words will be the sum of all three cases.

Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83

8 0
4 years ago
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Two similar trapezoids have areas
puteri [66]
It d i hope this helps
3 0
3 years ago
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