Answer:
D) ["Kathy Bones", "Jill Brewer", "Joe Schnook", "Tom Smith"]
Explanation:
The context of the problem explains a computer program that sorts names in "ascending order" (A to Z) since the ASCII table has capital A start a lower number and it increases from there to capital Z.
Notice how the attached file, which is a portion of the ASCII table, shows that letters after A are also higher in decimal value than the previous letter.
With this in mind, we know that all this program does is sort by last name alphabetical order. From there, just sort the given names using that same criteria, last name alphabetical order, and the correct answer is determined.
<em>Please put "Brainliest" on my answer if it helped you out!</em>
<em>If you want to learn more about this subject, you can search:</em>
<em>- ASCII Table</em>
<em>- Lists in Programming</em>
<em>- Sorting Procedures</em>
I think coders put in codes. Sry if that does not help.
Answer:
"True" Machine code and Object code is the same.
Explanation:
All code at the same level is considered the same code, so we can say that the machine code, byte code, and the object code with it is of the same type, all of which are considered as the lowest level associated with the common program, these are common. Also known as source code because it is used in translating different languages.
Explanation:
Let, DG is the datagram so, DG= 2400.
Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.
Let, M is the MTU so, M=700.
Let, IP is the IP header so, IP= 20.
Let, id is the identification number so, id=422
Required numbers of the fragment = ![[\frac{DG-IP}{M-IP} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7BDG-IP%7D%7BM-IP%7D%20%5D)
Insert values in the formula = ![[\frac{2400-20}{700-20} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2400-20%7D%7B700-20%7D%20%5D)
Then, =
= ![[3.5]](https://tex.z-dn.net/?f=%5B3.5%5D)
The generated numbers of the fragment is 4
- If FV = 1 then, bytes in data field of DG=
and id=422 and FO=0 and F=1.
- If FV = 2 then, bytes in data field of DG=
and id=422 and FO=85
and F=1.
- If FV = 3 then, bytes in data field of DG=
and id=422 and FO=170
and F=1.
- If FV = 4 then, bytes in data field of DG=
and id=422 and FO=255
and F=0.