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Tom [10]
3 years ago
14

Adrianna has fabric that is 3/4 yards long. She needs to cut the fabric into pieces that are are 1/8 yards long. How many 1/8 ya

rd-long pieces will she have?
Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:6 pieces

Step-by-step explanation:

3/4 can be made into 6/8. She will have 6 pieces

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Which is greater 5.97 or 5.946????
Ivenika [448]

Answer:

5.97

Step-by-step explanation:

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Can someone please help me with 11*3,56980
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The answer is 3,926,780 when you times 11 to 3,56980
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What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

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2 years ago
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A recent study examined hearing loss data for 1981 U.S. teenagers. In this sample, 369 were found to have some level of hearing
ruslelena [56]

Answer:

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

P-value=0.12

Step-by-step explanation:

We have to perform a test of hypothesis on the proportion.

The claim is that the proportion of US teens that have some level of hearing loss differs from 20%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.20\\\\H_a:\pi\neq0.20

The significance level is assumed to be 0.05.

The sample, of size n=1981, has 369 positive cases. Then, the proportion is:

p=X/n=369/1981=0.186

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.2*0.8}{1981}}=\sqrt{ 0.000081 }= 0.009

Now, we can calculate the statistic z:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.186-0.20+0.5/1981}{0.009}=\dfrac{-0.014}{0.009}=-1.556

The P-value for this two-tailed test is:

P-value=2*P(z

The P-value is below the significance level, so the effect is not significant. The null hypothesis failed to be rejected.

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

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Nadusha1986 [10]

Answer:

150 in^2

Step-by-step explanation:

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