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tekilochka [14]
3 years ago
13

Calculate the density of the baseball. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Deter

mine whether the density of baseball is within the legitimate range for an official baseball. Record your answers in Table C of your Student Guide. What is the density of the baseball?
Physics
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:

0.73 g/cm3 and yes are the correct answer choices.

garik1379 [7]3 years ago
4 0

Answer: 0.73 g/cm3 and YES the questionable ball in this range of acceptable density

Explanation:

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motikmotik

To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

F_{initial} = \frac{kq_1q_2}{r^2}

Here,

k = Coulomb's constant

q_{1,2} = Charge at each object

r = Distance between them

As the distance is doubled so,

F_{final} = \frac{kq_1q_2}{( 2r )^2}

F_{final} = \frac{ kq_1q_2}{ 4r^2}

F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}

F_{final} = \frac{1}{4} F_{initial}

\frac{F_{final}}{ F_{initial}} = \frac{1}{4}

Therefore the factor is 1/4

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3 years ago
What is required for both the light-dependent and light-independent reactions to proceed?
djyliett [7]
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3 years ago
Based on the diagram of the two electrical circuits, assuming the lightbulbs are all identical, which circuit will draw more pow
pochemuha
In series connection  in orde to find the total resistance we add all the resistance capacity but in parallel, we take the 1/R  and resistance = V  hence the series connection takes up more power,
8 0
4 years ago
Consider the electric force between a pair of charged particles a certain distance apart. By Coulomb's Law: If instead, the char
Westkost [7]

Answer:

the answer is d

Explanation:

from F=Q1Q2

r².

then wen both charges are doubled

F=2Q1 ×2Q2

r²

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then 4 has to be the factor multiplied by the other part of the equation for it to balance

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5 0
3 years ago
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When the life preserver is dropped from the helicopter, the only force acting on the object is the gravitational force. This modifies the equations of motion. Thus, the working equation is written below:

h = vt + 0.5gt²
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h = (1.46 m/s)(1.8 s) + 0.5(9.81 m/s²)(1.8 s) 
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3 years ago
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